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# An eight-card deck consists of 4 pairs of each suit. 2 cards

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An eight-card deck consists of 4 pairs of each suit. 2 cards [#permalink]

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03 Sep 2006, 10:03
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

An eight-card deck consists of 4 pairs of each suit. 2 cards are taken at random without repetition. What is the probability to have two cards of the same suit?
A. 1/2
B. 1/3
C. 1/4
D. 1/7
E. 1/8
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03 Sep 2006, 17:23
gk3.14 wrote:
An eight-card deck consists of 4 pairs of each suit. 2 cards are taken at random without repetition. What is the probability to have two cards of the same suit?
A. 1/2
B. 1/3
C. 1/4
D. 1/7
E. 1/8

4c1 * 2c1*1c1/8c2 = 1/7

??
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03 Sep 2006, 20:02
My answer is D (1/7) as well.

The way I looked at it

P1 = The probability of getting a card of any of the 4 suits = 8/8
P2 = The probability of getting the card of the same suit as the one taken first w/o repetition = 1/7

P = P1*P2
= 8/8 * 1/7
= 1/7
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03 Sep 2006, 22:38
D

For 1 suit:
First card = 2/8
Second card = 1/7
Total = 2/56

For 4 suit = 2/56 * 4 = 1/7
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

03 Sep 2006, 22:38
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