An electronics salesman earned a x% commission on each of
the m digital music player he sold in the month of March at the
retail price of $p. In April, he earned a y% commission on sales
of the same item, and the price remained the sale. If y > x and
he sold q more digital music players in April than in March, how
much more money did he earn selling digital music players in
April than in March?
(A) p/100 [ym - x(m + q)]
(B) p/100 [x(m + q) + ym]
(C) p[y(m - q) - xm]
(D) p/100 [x(m + q) - ym]
(E) p/100 [y(m + q) - xm]
KUDOS please if you like my question
If you lay out the facts, it's not nearly as daunting as it looks.
- x% commission on m players @ p price.
- y% commission on m players @ p price.
y>x AND he sold q more players in APRIL.
You can immediately eliminate C because it doesn't change the percentage into a dollar value (MUST have p/100 to accomplish this. The question asks how much more money?), so you're down to A,B,D,E
. Has (m+q)x which doesn't fit the given fact :q more players in April (q needs to multiplied by y)
. Adds y and x together - fails to answer the question. You need to subtract y from x to determine how much more money he earned.
. Had the difference backwards, you're subtracting y from x here and not x from y.
. All the elements are there, y(m+q), correct order of subtraction, and p/100.
You solved the question that is the main thing but how much time it took that is to be considered. I generally find these questions by assigning some value to them and then solve within 45 seconds. Without putting value sometimes it just gets tricky and you have to look over again and again.