This is the strategy that I use when I solve DS problems.

1. Break down the question into the simplest possible terms so that evaluation of the statements given becomes easier. For instance, if the question says \(|x-2| = 1\), then break it down as \((x-2) = +1\) and \((x-2) = -1\). This gives us \(x = 3\) and \(x = 1\). Definitely easier to solve the statements for accuracy based on the simplification rather than the initial form.

2. Read Statement 1. Evaluate whether it satisfies the mentioned condition. If it does, then you can safely strike out answer choices B, C and E since these are dependent on A being wrong. If A is wrong or incomplete, then you can strike out answer choices A and D.

3. Read Statement 2 now. Evaluate whether it's right or not. If A was already right, and B is also right, then the answer is D. If A was wrong, and B is also wrong, then the answer choice is C or E. If A was wrong and B is right, then the answer choice is B.

4. If A and B are individually both wrong, then read the statements together. If they make sense, then the answer choice is C. If not, the answer choice is B.

Here's a flowchart to better understand this:

Attachment:

Flowchart .jpg [ 87.76 KiB | Viewed 2765 times ]
Hope this helps.