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An exam consists of 8 true/false questions. Brian forgets to [#permalink]
23 Jul 2014, 21:18

7

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

60% (03:03) correct
40% (01:50) wrong based on 82 sessions

An exam consists of 8 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?

Re: An exam consists of 8 true/false questions. Brian forgets to [#permalink]
23 Jul 2014, 21:34

1

This post received KUDOS

maggie27 wrote:

An exam consists of 8 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?

A) 1/16 B) 37/256 C) 1/2 D) 219/256 E) 15/16

Since 70% is the passing rate, .70 ( 8 questions) = 5.6 correct answers (or 6 rounded up)

We must then look for the probability of passing: All correct answers + 7 correct answers + 6 correct answers = probability of passing.

An exam consists of 8 true/false questions. Brian forgets to [#permalink]
24 Jul 2014, 07:49

maggie27 wrote:

An exam consists of 8 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?

A) 1/16 B) 37/256 C) 1/2 D) 219/256 E) 15/16

I am not sure if the wording of the question is accurate. Anyone else feels the same way?

There are only two possibilities - Either Brian fails or he passes. So, probability that Brian passes = 1/2

Did I read the question incorrectly or is the wording ambiguous?

An exam consists of 8 true/false questions. Brian forgets to [#permalink]
24 Jul 2014, 07:56

1

This post received KUDOS

Expert's post

Game wrote:

maggie27 wrote:

An exam consists of 8 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?

A) 1/16 B) 37/256 C) 1/2 D) 219/256 E) 15/16

I am not sure if the wording of the question is accurate. Anyone else feels the same way?

There are only two possibilities - Either Brian fails or he passes. So, probability that Brian passes = 1/2

Did I read the question incorrectly or is the wording ambiguous?

No, that's not correct. According to your logic the probability of me dating Charlize Theron is also 1/2. Either yes or no. Wish this was true. _________________

Re: An exam consists of 8 true/false questions. Brian forgets to [#permalink]
24 Jul 2014, 17:20

Bunuel wrote:

Game wrote:

maggie27 wrote:

An exam consists of 8 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?

A) 1/16 B) 37/256 C) 1/2 D) 219/256 E) 15/16

I am not sure if the wording of the question is accurate. Anyone else feels the same way?

There are only two possibilities - Either Brian fails or he passes. So, probability that Brian passes = 1/2

Did I read the question incorrectly or is the wording ambiguous?

No, that's not correct. According to your logic the probability of me dating Charlize Theron is also 1/2. Either yes or no. Wish this was true.

OK. Got it. On a side note, probability of you dating Charlize Theron is 0 & here is the mathematical explanation for the math expert:

Assuming Charlize Theron (C.T.) will date only one person at a time Probability(Game dating C.T.) + Probability(Bunuel dating C.T.) + ... = 1 Since Probability(Game dating C.T.) = 1 Probability(Bunuel dating C.T.) + ... = 1 - 1 = 0

An exam consists of 8 true/false questions. Brian forgets to [#permalink]
09 Aug 2014, 14:54

1

This post was BOOKMARKED

An exam consists of 8 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?

Re: An exam consists of 8 true/false questions. Brian forgets to [#permalink]
09 Aug 2014, 16:02

An exam consists of 8 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?

If you have 8 T or F and Brian is going to guess then each question he has a 50% chance of getting correct.

If a passing score is 70% it means Brian needs to get 6/8=75%, 7/8=87.5%, or 8/8=100% to pass. Each is a possibility. If Brian gets a 5/8(=62.5%) or below he fails.

So first figure out the number of ways that Brian can get 6 out of 8, 7 out of 8, and 8 out of 8 questions correct. Which is 8 choose 6, equals is 28, 8 choose 7, equals 8, and 8 choose 8, equals 1. This sums to 37.

The number of possible questions outcomes -the sum of 8 choose 8, 7 choose 8, 6 choose 8….2 choose 8, 1 choose 8, and 0 choose 8 is 256, so the chance of him passing is 37/256.

I know there is a shorter way, but this is how I did it in about 2:34

Re: An exam consists of 8 true/false questions. Brian forgets to [#permalink]
10 Aug 2014, 00:35

2

This post received KUDOS

If you have True or False question, then each question has a \frac{1}{2} chance of getting correct.

If a passing score is 70% it means Brian needs to get right or 6 questions (6/8=75%), or 7 questions (7/8=87.5%), or 8 questions (8/8=100%).

The probability to have all 8 questions right is: \frac{1}{2^8} The probability to have 7 questions right and 1 wrong is: C_8^1*\frac{1}{2^7}*\frac{1}{2}=\frac{8}{2^8} (choose this incorrect answer C_8^1, probability to have 7 right \frac{1}{2^7}, and probability to have 1 wrong \frac{1}{2}) The probability to have 6 questions right and 2 wrong is: C_8^2*\frac{1}{2^6}*\frac{1}{2^2}=\frac{28}{2^8} (choose the se 2incorrect answers C_8^2, probability to have 6 right \frac{1}{2^6}, and probability to have 2 wrong \frac{1}{2^2})

The probability is \frac{1}{2^8}+\frac{8}{2^8}+\frac{28}{2^8}=\frac{37}{256} _________________

I'm happy, if I make math for you slightly clearer And yes, I like kudos:)

Re: An exam consists of 8 true/false questions. Brian forgets to [#permalink]
14 Dec 2014, 04:06

Bunuel wrote:

Game wrote:

maggie27 wrote:

An exam consists of 8 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?

A) 1/16 B) 37/256 C) 1/2 D) 219/256 E) 15/16

I am not sure if the wording of the question is accurate. Anyone else feels the same way?

There are only two possibilities - Either Brian fails or he passes. So, probability that Brian passes = 1/2

Did I read the question incorrectly or is the wording ambiguous?

No, that's not correct. According to your logic the probability of me dating Charlize Theron is also 1/2. Either yes or no. Wish this was true.

I have a very basic and silly doubt Why the probability of getting 7 right is 8c1/(1/2^8)

I mean i understood the denominator part but why 8c1? As it has to be 7 answers out of 8... So i thought it will be 2^7/2^8

Re: An exam consists of 8 true/false questions. Brian forgets to [#permalink]
15 Dec 2014, 06:26

Expert's post

gauriranjekar wrote:

I have a very basic and silly doubt Why the probability of getting 7 right is 8c1/(1/2^8)

I mean i understood the denominator part but why 8c1? As it has to be 7 answers out of 8... So i thought it will be 2^7/2^8

Please help..!!

Because 7 correct out of 8 can occur in 8 ways: YYYYYYYN (first 7 correct and 8th not). YYYYYYNY YYYYYNYY YYYYNYYY YYYNYYYY YYNYYYYY YNYYYYYY NYYYYYYY _________________

Re: An exam consists of 8 true/false questions. Brian forgets to [#permalink]
26 Jan 2015, 03:28

Expert's post

maggie27 wrote:

An exam consists of 8 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?

First, Brian must get 70% of the 8 questions right to pass. 70% of 8 is 5.6, though, so he must get 6 questions right (there's no such thing as "partial credit" on a true/false question). This leaves us with three possible outcomes:

6 right, 2 wrong

7 right, 1 wrong

8 right, 0 wrong

We can use our knowledge of permutations with identical elements to calculate the probability here since, for our purposes, a correct answer on the first question is the same as a correct answer on the third question. Thus, there are 8!/(6!2!), or 28, ways to get 6 questions right, 8!/7!, or 8, ways to get 7 questions right, and only 1 way to get all 8 of the questions right. Brian has a total of 37 good outcomes. The number of possible outcomes, though, is 2^8, or 256, giving Brian a 37/256 chance of passing. Good luck, Brian!

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