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An integer when divided by 12 leaves remainder 0,when

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CEO
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An integer when divided by 12 leaves remainder 0,when [#permalink] New post 06 Oct 2003, 01:26
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An integer when divided by 12 leaves remainder 0,when divided by 11 leaves remainder 7, what is the remainder when
divided by 8?
Manager
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Joined: 27 Jul 2003
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 [#permalink] New post 06 Oct 2003, 01:40
It should be 4.

Since, 12 - 11 = 1
To find out the number, multiply 12 by (7/1) = 84 {
11 * 7 =77 }
{ check out with examples.. }
so, remainder when divided by 8 = 4
Ans. 4

Another approach 11x + 7 = 12x
X = 7 => the integer is 84
Divided by 8 gives 4 as remainder
CEO
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 [#permalink] New post 06 Oct 2003, 01:50
araspai wrote:
It should be 4.

Since, 12 - 11 = 1
To find out the number, multiply 12 by (7/1) = 84 {
11 * 7 =77 }
{ check out with examples.. }
so, remainder when divided by 8 = 4
Ans. 4

Another approach 11x + 7 = 12x
X = 7 => the integer is 84
Divided by 8 gives 4 as remainder


Do i think you are who i think you are :)

I disagree with your second approach..

the x's are not same.

x = 11 A + 7
x = 12 B

A not equal to B.

I got remainder 0.

thanks
praetorian
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 [#permalink] New post 06 Oct 2003, 01:53
I know who you are . Houston_youve_gotta_problem.
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 [#permalink] New post 06 Oct 2003, 01:53
I know who you are . Houston_youve_gotta_problem.
CEO
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Kudos [?]: 654 [0], given: 781

 [#permalink] New post 06 Oct 2003, 02:01
araspai wrote:
I know who you are . Houston_youve_gotta_problem.


thanks for broadcasting my email address :lol:
CEO
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Kudos [?]: 654 [0], given: 781

 [#permalink] New post 06 Oct 2003, 02:48
stolyar wrote:
got 84 by simple guessing
R=4


stolyar

could you explain please

This is how i did it

x = 12m
x = 11n + 7

12m = 11n + 7
m = (11n+ 7)/12

We know m is an integer ...so 11n+7 is a multiple of 12..
n = 7 , m = 84

so .. x = 12 * 84

x divided by 8 will have remainder 0.
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 [#permalink] New post 06 Oct 2003, 03:30
84=11*7+7
84=12*7

the last digit (4) should be the same

84=8*10+4

R=4
CEO
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 [#permalink] New post 06 Oct 2003, 13:41
stolyar wrote:
84=11*7+7
84=12*7

the last digit (4) should be the same

84=8*10+4

R=4


oh ..i did a simple mistake

n = 7 will give m= 7 ..

x =12*7 = 84

Remainder = 4

Thanks
Praetorian
  [#permalink] 06 Oct 2003, 13:41
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