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An operation @ is defined by the equation a@b = (a - b) / (a

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An operation @ is defined by the equation a@b = (a - b) / (a [#permalink]

13 Dec 2012, 10:14

00:00

Question Stats:

83% (01:37) correct

16% (00:20) wrong

based on 30 sessions

An operation @ is defined by the equation a@b = (a - b) / (a + b), for all numbers a and b such that a ≠ -b. If a ≠ -c and a@c = 0, then c =

(A) -a
(B) -1/a
(C) 0
(D) 1/a
(E) a

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Re: An operation @ is defined by the equation a@b = (a - b) / (a [#permalink]

13 Dec 2012, 10:16

Walkabout wrote:

An operation @ is defined by the equation a@b = (a - b) / (a + b), for all numbers a and b such that a ≠ -b. If a ≠ -c and a@c = 0, then c =

(A) -a
(B) -1/a
(C) 0
(D) 1/a
(E) a

Given that a@b = \frac{a - b}{a + b}, thus a@c = \frac{a - c}{a + c}.

Also given that a@c = \frac{a - c}{a + c}=0 --> a-c=0 --> a=c.

Answer: E.
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Re: An operation @ is defined by the equation a@b = (a - b) / (a [#permalink] 13 Dec 2012, 10:16

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An operation @ is defined by the equation a@b = (a - b) / (a

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An operation @ is defined by the equation a@b = (a - b) / (a

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