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Andrew and Stephen drive on the highway in the same direction at respe [#permalink]

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22 Apr 2009, 17:49

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78% (02:40) correct
22% (02:00) wrong based on 310 sessions

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Andrew and Stephen drive on the highway in the same direction at respective rates of 72 and 80 kmh. If Stephen is 4 km behind Andrew, by how much does he have to increase his speed to catch up with Andrew in 20 minutes?

Re: Andrew and Stephen drive on the highway in the same direction at respe [#permalink]

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02 May 2009, 15:25

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relative speed=80-72=8 need to catch up 4km

currently Stephen is catching up at a speed of 4km/30mins, or 2km/15mins he needs to increase the speed, so that he can make 4km in 20 mins instead, or 1km/5mins

x - the relative speed increase we seek 2/15+x=1/5 x=1/15

So, he needs to increase relative speed by 1km per 15mins, or 4km/h Therefore, the answer is D.

Re: Andrew and Stephen drive on the highway in the same direction at respe [#permalink]

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25 Jul 2009, 13:42

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I think its much easier to first assume that they are going the same speed. So he has to catch up 4 meters in 1/3 hour. r= d/t = 4/(1/3) = 12 km/hr faster he has to go. He is already going 8km/h faster, so 12 - 8 = 4 km/hr

Re: Andrew and Stephen drive on the highway in the same direction at respe [#permalink]

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25 Jul 2009, 14:40

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benpack03 wrote:

I think its much easier to first assume that they are going the same speed. So he has to catch up 4 meters in 1/3 hour. r= d/t = 4/(1/3) = 12 km/hr faster he has to go. He is already going 8km/h faster, so 12 - 8 = 4 km/hr

Yes! That's what I also came up with. _________________

Re: Andrew and Stephen drive on the highway in the same direction at respe [#permalink]

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18 Oct 2014, 08:55

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Re: Andrew and Stephen drive on the highway in the same direction at respe [#permalink]

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19 Oct 2014, 02:58

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bigfernhead wrote:

Andrew and Stephen drive on the highway in the same direction at respective rates of 72 and 80 kmh. If Stephen is 4 km behind Andrew, by how much does he have to increase his speed to catch up with Andrew in 20 minutes?

A. 1 kmh B. 2 kmh C. 3 kmh D. 4 kmh E. 5 kmh

M17-37

Denote the required acceleration as \(x\). The distance between Andrew and Stephen will be decreasing at \((80 + x - 72)\) kmh. We can compose the equation \(\frac{4}{80 + x - 72} = \frac{20}{60}\) from which \(x = 4\).

Re: Andrew and Stephen drive on the highway in the same direction at respe [#permalink]

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12 Nov 2015, 00:03

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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