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Angela’s grade was in the 90th percentile out of 80 grades i

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Angela’s grade was in the 90th percentile out of 80 grades i [#permalink] New post 23 Oct 2009, 11:57
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Angela’s grade was in the 90th percentile out of 80 grades in her class. In another class of 100 students there were 19 grades higher than Angela’s. If nobody had Angela’s grade, then Angela was what percentile of the two classes combined?

a. 72
b. 80
c. 81
d. 85
e. 92

OPEN DISCUSSION OF THIS QUESTION IS HERE: angela-s-grade-was-in-the-90th-percentile-out-of-80-grades-106011.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 27 Sep 2013, 06:56, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Percentile [#permalink] New post 23 Oct 2009, 13:11
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study wrote:
Angela’s grade was in the 90th percentile out of 80 grades in her class. In another class of 100 students there were 19 grades higher than Angela’s. If nobody had Angela’s grade, then Angela was what percentile of the two classes combined?

a. 72
b. 80
c. 81
d. 85
e. 92


Being in 90% percentile out of 80 grades means Amy was 73rd (from the least grade) in the class (as long as nobody had Amy's grades), she outscored 72.

In another class her grade would rank her 82 (from the least grade out of 101, 100+Amy), 81 had the grades lower than Amy.

So in combined classes she outscored 72+81=153. There are 180 students 153/180=0.85

Answer: D (85%)

Generally being in x% means that x% has the grades less than you.

Amy in 90% --> she outscored 90% of of 80=72 (Amy is 73rd).
Of the 100 grades from another class, 19 were higher than Amy's, and the rest were lower --> rest is 81, hence Amy outscored 81.

So out of total 80+100=180, Amy outscored 72+81=153. Hence she is in 153/180=85%.

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Re: Percentile [#permalink] New post 17 May 2011, 22:56
in class A, 8 grades are above Angela's meaning 72 people behind her.
in class B, 19 grades are above Angela's meaning 81 people are behind her.

thus 72+81/(100+80) = 153/180 = 85 percentile

153 people are behind Angela's score.

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Re: Percentile [#permalink] New post 27 Sep 2013, 06:16
Bunuel wrote:
study wrote:
Angela’s grade was in the 90th percentile out of 80 grades in her class. In another class of 100 students there were 19 grades higher than Angela’s. If nobody had Angela’s grade, then Angela was what percentile of the two classes combined?

a. 72
b. 80
c. 81
d. 85
e. 92


Being in 90% percentile out of 80 grades means Amy was 73rd (from the least grade) in the class (as long as nobody had Amy's grades), she outscored 72.

In another class her grade would rank her 82 (from the least grade out of 101, 100+Amy), 81 had the grades lower than Amy.

So in combined classes she outscored 72+81=153. There are 180 students 153/180=0.85

Answer: D (85%)

Generally being in x% means that x% has the grades less than you.

Amy in 90% --> she outscored 90% of of 80=72 (Amy is 73rd).
Of the 100 grades from another class, 19 were higher than Amy's, and the rest were lower --> rest is 81, hence Amy outscored 81.

So out of total 80+100=180, Amy outscored 72+81=153. Hence she is in 153/180=85%.


Hi,

How were you able to understand that in the first class there were 80 students, and in the second one there were 101 and not 100?
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Re: Percentile [#permalink] New post 27 Sep 2013, 06:58
Expert's post
ronr34 wrote:
Bunuel wrote:
study wrote:
Angela’s grade was in the 90th percentile out of 80 grades in her class. In another class of 100 students there were 19 grades higher than Angela’s. If nobody had Angela’s grade, then Angela was what percentile of the two classes combined?

a. 72
b. 80
c. 81
d. 85
e. 92


Being in 90% percentile out of 80 grades means Amy was 73rd (from the least grade) in the class (as long as nobody had Amy's grades), she outscored 72.

In another class her grade would rank her 82 (from the least grade out of 101, 100+Amy), 81 had the grades lower than Amy.

So in combined classes she outscored 72+81=153. There are 180 students 153/180=0.85

Answer: D (85%)

Generally being in x% means that x% has the grades less than you.

Amy in 90% --> she outscored 90% of of 80=72 (Amy is 73rd).
Of the 100 grades from another class, 19 were higher than Amy's, and the rest were lower --> rest is 81, hence Amy outscored 81.

So out of total 80+100=180, Amy outscored 72+81=153. Hence she is in 153/180=85%.


Hi,

How were you able to understand that in the first class there were 80 students, and in the second one there were 101 and not 100?


Angela’s grade was in the 90th percentile out of 80 grades in her class. In another class of 100 students...

OPEN DISCUSSION OF THIS QUESTION IS HERE: angela-s-grade-was-in-the-90th-percentile-out-of-80-grades-106011.html

_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: Percentile   [#permalink] 27 Sep 2013, 06:58
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