20 % ?
total number of ways of selecting 2 commities of 3 each from 6ppl = 6C3 = 20
Now michael and anthony are together the 3rd person in the committee is one of the 4 remaining so 4 ways
% 4/20 * 100 = 20
But there are two committees, so 4*2/20=2/5
are u saying 6c2 is the number of ways the first commitee can be set up and each time the remaining 3 form one comittee?
then the number of committes per say will be 6c2 x 2 but ways inwhich commites can be formed is 6c2.
now committees with both of them in could be 4 x2 . same group as a comitte for 2 functions
so answer = 2x4/6c2x2 = 20%
Can we assume that same group can be considered as 2 comittes? working on both the functions .
i am :confused