Th total number of ways a group of 3 can be formed is (6*5*4). Probability = 1/5.
Paddyboy, I beg to differ with you.
The order of members within the group is not
significant. Thus, the number of 3 member groups that can be formed will be 6C3 = 20 and not 6P3.
Also, if Anthony and Michael are to come in 1 group together, the number of groups that can be formed are 5C3 = 5C2 = 10.
Hence, %age = 10/20 = 50%.
IMO answer should be (D).
Am very weak in probability and permutation-combinations. So kindly let me know if there is an issue with my approach to this problem.