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Anthony and Michael sit on the six-member board of directors

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Anthony and Michael sit on the six-member board of directors [#permalink]

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New post 12 Dec 2006, 15:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?
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Senior Manager
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New post 12 Dec 2006, 15:44
5C2 = 10 = total no of committees with michael on them
4C1 = 4 = total no of committees with michael and anthony

100*4/10 = 40%
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New post 15 Dec 2006, 21:41
total = 5C2= 10
fav = treat the two as one unit.
1C1* 4C1=4

Percentage = 4/10=40%

what is the OA ?
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Re: MGMAT -- Probability [#permalink]

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New post 15 Dec 2006, 21:53
favourable ways = 4c1 =4 ways
total ways = 5c2 =10 ways

hence 4/10 *100=40 %
Re: MGMAT -- Probability   [#permalink] 15 Dec 2006, 21:53
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Anthony and Michael sit on the six-member board of directors

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