Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 05 May 2015, 05:45

# Expecting Soon:

Wharton Round 3 Decisions.   |   Join Chat Room for Live Updates

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Anthony and Michael sit on the six-member board of directors

Author Message
TAGS:
Director
Joined: 08 Feb 2007
Posts: 610
Location: New Haven, CT
Followers: 5

Kudos [?]: 17 [0], given: 0

Anthony and Michael sit on the six-member board of directors [#permalink]  23 Jul 2007, 09:54
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?

a. 30%
b. 40%
c. 50%
d. 60%
e. 70%
Senior Manager
Joined: 04 Jun 2007
Posts: 348
Followers: 1

Kudos [?]: 15 [0], given: 0

Re: PS: comb/perm [#permalink]  23 Jul 2007, 09:59
lanter1 wrote:
Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?

a. 30%
b. 40%
c. 50%
d. 60%
e. 70%

B (40%) for me.

No. of sub-committees including Michael = 5C2 (M _ _) = 10
No. of sub-committees including Michael and Anthony = 4C1 (M A _) = 4
Answer = (4/10) * 100 = 40%
Senior Manager
Joined: 28 Jun 2007
Posts: 463
Followers: 2

Kudos [?]: 5 [0], given: 0

Can u explain how u arrived at 5C2 ??? Thanks in advance.
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5078
Location: Singapore
Followers: 22

Kudos [?]: 184 [0], given: 0

If the sub-committee already has michael on board, then the remaining two seats can be filled in 5C2 ways = 10

If the sub-committee has both michael and anthony, then the remaining seat can be filled 4 ways.

P = 4/10 = 2/5 = 40%
Senior Manager
Joined: 28 Jun 2007
Posts: 463
Followers: 2

Kudos [?]: 5 [0], given: 0

ywilfred wrote:
If the sub-committee already has michael on board, then the remaining two seats can be filled in 5C2 ways = 10

If the sub-committee has both michael and anthony, then the remaining seat can be filled 4 ways.

P = 4/10 = 2/5 = 40%

But Isnt the question a little different?

I would think they are asking for No. of Teams comprising both/ no. of Teams comprising one alone

GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5078
Location: Singapore
Followers: 22

Kudos [?]: 184 [0], given: 0

ioiio wrote:
ywilfred wrote:
If the sub-committee already has michael on board, then the remaining two seats can be filled in 5C2 ways = 10

If the sub-committee has both michael and anthony, then the remaining seat can be filled 4 ways.

P = 4/10 = 2/5 = 40%

But Isnt the question a little different?

I would think they are asking for No. of Teams comprising both/ no. of Teams comprising one alone

The question says 'what percent of all the possible subcommittees that include Michael also include Anthony? '

So it is looking for this percentage:

(All groupings that include Michael and Anthony)/(All groupings that include Michael) * 100%

So
All groupings that include Michael and Anthony -> you have to assume michael and anthony are already in the team, then the last seat can be just any one of the 4 remaining people

All groupings that include Michael -> you have to assume michale is already in the team, and the remaining two places can be filled by any 2 of the remaining 5 people, thus 5C2
Senior Manager
Joined: 17 Jul 2007
Posts: 288
Location: The 408
Followers: 3

Kudos [?]: 2 [0], given: 0

Re: PS: comb/perm [#permalink]  23 Jul 2007, 19:17
sumande wrote:
lanter1 wrote:
Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?

a. 30%
b. 40%
c. 50%
d. 60%
e. 70%

B (40%) for me.

No. of sub-committees including Michael = 5C2 (M _ _) = 10
No. of sub-committees including Michael and Anthony = 4C1 (M A _) = 4
Answer = (4/10) * 100 = 40%

I'm new, so pardon the dumb n00b question. what do the letters C, M, and A represent?

Thanks!
Senior Manager
Joined: 28 Jun 2007
Posts: 463
Followers: 2

Kudos [?]: 5 [0], given: 0

Re: PS: comb/perm [#permalink]  23 Jul 2007, 19:25
zakk wrote:
sumande wrote:
lanter1 wrote:
Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?

a. 30%
b. 40%
c. 50%
d. 60%
e. 70%

B (40%) for me.

No. of sub-committees including Michael = 5C2 (M _ _) = 10
No. of sub-committees including Michael and Anthony = 4C1 (M A _) = 4
Answer = (4/10) * 100 = 40%

I'm new, so pardon the dumb n00b question. what do the letters C, M, and A represent?

Thanks!

C is combination. Look up wiki for definition
M and A stand for Michael and Anthony.
Senior Manager
Joined: 21 Jun 2006
Posts: 287
Followers: 1

Kudos [?]: 30 [0], given: 0

2/5

Assume anthony is selected in the committee, that leaves 5 people of which 2 other members are selected

total combinations of selecting 2 out of 5 = 5C2 = 10

Now, for michael to be one of the two there are 4C1 combinations = 4
i.e.
assume michael is fixed and the other can be anyone
4/10 = 2/5
Similar topics Replies Last post
Similar
Topics:
Anthony and Michael sit on the six-member board of directors 3 12 Dec 2006, 14:38
Anthony and Michael sit on the six-member board of directors 9 01 Nov 2006, 08:56
Anthony and Michael sit on the six-member board of directors 3 16 Aug 2006, 10:51
Anthony and Michael sit on the six-member board of directors 4 14 Aug 2006, 19:52
Anthony and Michael sit on the six-member board of directors 9 05 Feb 2006, 21:35
Display posts from previous: Sort by