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Any decimal that has only a finite number of nonzero digits

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Any decimal that has only a finite number of nonzero digits [#permalink] New post 20 Aug 2009, 04:43
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1)Any decimal that has only a finite number of nonzero digits is a terminating decimal. For example, 36, 0.72, and 3.005 are terminating decimals. If a, b, c, d and e are integers and p= 2^a3^b and q = 2^c3^d5^e , is p/q a terminating decimal?

1) a > c
2) b> d


Please explain your answer
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Re: Is p/p terminating decimal? [#permalink] New post 20 Aug 2009, 05:52
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p/p=1, man :D

the question is:
p= 2^a*3^b and q = 2^c*3^d*5^e , is p/q a terminating decimal?

p/q=2^(a-c)*3^(b-d)*5^(-c)
therefore, as long as (b-d)>0, p/q is terminating

Answer B
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Re: Is p/q terminating decimal? [#permalink] New post 20 Aug 2009, 09:08
Yup B.
Stmt 2 is sufficient to ensure that all 3's in the denominator are cancelled out and hence we will always have a terminating decimal
Re: Is p/q terminating decimal?   [#permalink] 20 Aug 2009, 09:08
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Any decimal that has only a finite number of nonzero digits

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