Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 04 May 2015, 18:14

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# any number when divided by 9, has a remainder equal to the

Author Message
TAGS:
VP
Joined: 30 Sep 2004
Posts: 1490
Location: Germany
Followers: 4

Kudos [?]: 91 [0], given: 0

any number when divided by 9, has a remainder equal to the [#permalink]  20 Feb 2005, 13:15
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
any number when divided by 9, has a remainder equal to the sum of its digits. if the last digit of a seven digit number is 4 and the remaining six digits add up to 23, then the original number must be

a divisible by 7
b divisible by 18
c divisible by 23
d divisible by 27
e a prime number
Intern
Joined: 19 Feb 2005
Posts: 9
Followers: 0

Kudos [?]: 0 [0], given: 0

B for me too

its divisible by 9... sum is 27
and its divisible by 2.. . ends with a 4

divisible by 18
Manager
Joined: 01 Feb 2005
Posts: 63
Location: NYC
Followers: 1

Kudos [?]: 0 [0], given: 0

Why do we need this first sentence in the question?

â€œany number when divided by 9, has a remainder equal to the sum of its digitsâ€
Senior Manager
Joined: 19 Feb 2005
Posts: 487
Location: Milan Italy
Followers: 1

Kudos [?]: 11 [0], given: 0

so the rule is
the sum of the digits of a multiple of 9 is 9?
VP
Joined: 25 Nov 2004
Posts: 1495
Followers: 6

Kudos [?]: 38 [0], given: 0

thearch wrote:
so the rule is
the sum of the digits of a multiple of 9 is 9?

yes!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
VP
Joined: 18 Nov 2004
Posts: 1442
Followers: 2

Kudos [?]: 20 [0], given: 0

can anyone tell me what is this sentence for "any number when divided by 9, has a remainder equal to the sum of its digits"
SVP
Joined: 03 Jan 2005
Posts: 2250
Followers: 13

Kudos [?]: 216 [0], given: 0

ETS doesn't assume you have this knowledge, and doesn't require you to have this knowledge. For people who don't know this rule, this information is required to solve the problem.
VP
Joined: 18 Nov 2004
Posts: 1442
Followers: 2

Kudos [?]: 20 [0], given: 0

HongHu wrote:
ETS doesn't assume you have this knowledge, and doesn't require you to have this knowledge. For people who don't know this rule, this information is required to solve the problem.

ok, then is this rule saying that when 9 divided by 9 leaves a remainder of 9 ? It is talking abt "any" number. What abt non integer numbers ? Doesn't seem to be correct rule.
SVP
Joined: 03 Jan 2005
Posts: 2250
Followers: 13

Kudos [?]: 216 [0], given: 0

Yes, it is not formulated correctly, I would say. What if the sum of the digits are 14? You need to sum it again until the sum is less than 9.

Also, when we talk about reminders, we are usually talking about integers.
Current Student
Joined: 28 Dec 2004
Posts: 3391
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 13

Kudos [?]: 181 [0], given: 2

here is why....maybe it can help those who dont know these rules..(me )

well the last digit is 4 (which means its even, i.e divisible by 2)

the sum of the other remaining digits is 23...

hmm, all I know is that for a number to be divisible by 3, its sum must be divisible by 3... (so we have 23+4=27, which is divisible by 3!)

now, I know that this number cannot be a prime (because of the 4!)eliminate choice (e). Next lets look at 27...since 27 is the sum of the 4+23 above I guess its just a trap answer so eliminate (d). now look at 23, 23 is just one of the numbers from the question stem, eliminate it (C)...now we have B, 18, 18 is a product of 2 and 3. meets both criterias, therefore the likely answer...pick B.

Again I wont do this if I knew how to solve the problem, but I am guessing so why not put some thought into it!
Similar topics Replies Last post
Similar
Topics:
6 What is the remainder when 2^86 is divided by 9? 13 15 Apr 2014, 23:19
2 The lucky number trick: Remainder when divided by 9 2 08 May 2011, 02:31
1 When the positive integer x is divided by 9, the remainder 8 22 Nov 2007, 17:04
When a number divided by 35, the remainder is 2;divided by 8 06 Sep 2006, 01:37
When a number divided by 35, the remainder is 2;divided by 1 19 Aug 2006, 01:41
Display posts from previous: Sort by