Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 05 May 2015, 04:21

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# anyone want to take a shot at this Tanya prepared 4

Author Message
TAGS:
Manager
Joined: 14 May 2006
Posts: 57
Followers: 1

Kudos [?]: 2 [0], given: 0

anyone want to take a shot at this Tanya prepared 4 [#permalink]  17 Jun 2007, 19:01
anyone want to take a shot at this

Tanya prepared 4 different letters to be sent to 4 different addresses. For each letter, she prepared an envelop with its correct address. If the 4 letters are to be put into the 4 envelopes at random, what is the probability that only 1 letter will be put into the envelope with its correct address?

a) 1/24
b) 1/8
c) ¼
d) 1/3
e) 3/8

Dan
 Kaplan Promo Code Knewton GMAT Discount Codes Veritas Prep GMAT Discount Codes
Manager
Joined: 07 May 2007
Posts: 181
Followers: 2

Kudos [?]: 18 [0], given: 0

I got 1/12 which is not given in the choices!
Manager
Joined: 07 May 2007
Posts: 181
Followers: 2

Kudos [?]: 18 [0], given: 0

I got it

P = 4(1/4*2/3*1/2) = 1/3
Senior Manager
Joined: 21 Jun 2006
Posts: 287
Followers: 1

Kudos [?]: 30 [0], given: 0

Intern
Joined: 11 Feb 2007
Posts: 30
Followers: 0

Kudos [?]: 0 [0], given: 0

i got 1/4. what is the OA? how do you solve it?
Manager
Joined: 07 May 2007
Posts: 181
Followers: 2

Kudos [?]: 18 [1] , given: 0

1
KUDOS
This is how I looke at it:

Chance that 1st letter goes into correct address is 1/4
Chance that 2nd letter goes into incorrect address is 2/3 ( becos out of remaining 3 covers 2 carry incorrect addr for 2nd letter)
Chance that 3rd letter goes into incorrect address is 1/2 ( becos out of remaining 2 covers 1 carries incorrect addr for 3rd letter)
If all this happens, 4th letter should go into the wrong cover for sure. Chance = 1

For prob that one letter gets into correct address and others into wrong = 1/4*2/3*1/2*1 = 1/12 ---> This is where I stopped when I initially solved the problem.

But since there are 4 such permutations prob = 4*1/12 = 1/3

I don't know if this is the OA or not
Manager
Joined: 14 May 2006
Posts: 57
Followers: 1

Kudos [?]: 2 [0], given: 0

Thanks [#permalink]  18 Jun 2007, 15:33
Thanks

OA: d) 1/3

Dan
Senior Manager
Joined: 06 Jul 2004
Posts: 474
Location: united states
Followers: 1

Kudos [?]: 16 [0], given: 0

L1, L2, L3 and L4 are four letters
A1, A2, A3 and A4 are four addresses

with L1 in A1, each of the other three letters can go to two of the remaining envelopes. So, the total number of favourable outcomes are

1*2*2*2 = 8

total number of ways = 4!=24

P=8/24=1/3
_________________

for every person who doesn't try because he is
afraid of loosing , there is another person who
keeps making mistakes and succeeds..

Similar topics Replies Last post
Similar
Topics:
19 Tanya prepared 4 letters to be sent to 4 different 11 15 Oct 2006, 13:12
Tanya prepared 4 different letters to be sent to 4 different 5 16 Jun 2006, 21:37
Tanya prepared 4 letters to be sent to 4 different adresses. 4 05 Jun 2006, 04:03
Tanya prepared 4 different letters to be sent to 4 different 2 28 Jan 2006, 00:47
Tanya prepared 4 different letters to be sent to 4 different 7 26 Oct 2005, 21:18
Display posts from previous: Sort by

# anyone want to take a shot at this Tanya prepared 4

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.