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Are integers P and Q both multiples of 3? (1) PQ (a

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Are integers P and Q both multiples of 3? (1) PQ (a [#permalink] New post 08 Oct 2008, 23:38
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Are integers P and Q both multiples of 3?

(1) PQ (a two-digit number) is a multiple of 9
(2) Q is a multiple of 3
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Re: DS : Multiple 3 [#permalink] New post 09 Oct 2008, 00:36
IMO B

A:
18 , 36 so not suff.

B: as q is mulitple of 3 (0,3,6,9) then p will be (0 or 9,6,3,0 or 9).

* is 0 is muliple of 3 ?

but B is answer

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Re: DS : Multiple 3 [#permalink] New post 09 Oct 2008, 00:43
vr4indian wrote:
IMO B

A:
18 , 36 so not suff.

B: as q is mulitple of 3 (0,3,6,9) then p will be (0 or 9,6,3,0 or 9).

* is 0 is muliple of 3 ?

but B is answer

Thanks


How can you deduce the values of P from statement 2 ??
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Re: DS : Multiple 3 [#permalink] New post 09 Oct 2008, 03:17
amitdgr wrote:
Are integers P and Q both multiples of 3?

(1) PQ (a two-digit number) is a multiple of 9
(2) Q is a multiple of 3


1) includes 99,81,36 any 2 digit number which multiple of 9 hence P,Q can be multiples of 9 or may not be !!! ---> INSUFFI
2)theres no clue about P INSUFFI
Combine both again 99,36,63 are 3 numbers where Q is a multiple of 3 and P too is a multiple of 3 . IMO C
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Re: DS : Multiple 3 [#permalink] New post 09 Oct 2008, 03:33
1st eq is not suff.
Now lets assume 2nd statment correct thna half portion of questions solves.
So if Q is multiple of 3 that means Q can be 3,6,9 and so on

Now consider 1st Equation again
PQ is 2 digit number
P3,P6 & p9 can be 3 possibility of 2 digit number Now all these numbers are divisble by 9 means P can be 6, 3 or 9.
So both P & Q are multiple of 3.

Hence Answer is C) Both conditions together provides the answer.
Re: DS : Multiple 3   [#permalink] 09 Oct 2008, 03:33
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