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1 st)
2x-2y=1
x-y=1/2 insuff since x and y can be anything
x=1 and y=1/2 or x= -1/2 and y=-1
2) x/y >1 x and y may be both pos and both negative
-2/-1>1
E for me _________________

1 st) 2x-2y=1 x-y=1/2 insuff since x and y can be anything x=1 and y=1/2 or x= -1/2 and y=-1 2) x/y >1 x and y may be both pos and both negative -2/-1>1 E for me

E for me too ........ used the exact methodology and numbers

(1) 2x-2y = 1
x = y+ 1/2. x or y, both, could be either - or +.

(2) x/y >1.
x>y but both should be +ves.
x<y but both should be -ves.

togather:
if y = 0.5, x = 1 (and we have x/y = 1/0.5 = 2 which is greater than1).
ok, if y = -0.5, x = 0 (and we have x/y = 0 which isn't greater than1).

(1) 2x-2y = 1 x = y+ 1/2. x or y, both, could be either - or +.

(2) x/y >1. x>y but both should be +ves. x<y but both should be -ves.

togather: if y = 0.5, x = 1 (and we have x/y = 1/0.5 = 2 which is greater than1). ok, if y = -0.5, x = 0 (and we have x/y = 0 which isn't greater than1).

So E is it.

Prof, we cannot take this exemple simply because this exemple is not respecting statment 2. It respects the line equation but not x/y > 1. So it cannot be use to say answer (E) as well.

Prof, we cannot take this exemple simply because this exemple is not respecting statment 2. It respects the line equation but not x/y > 1. So it cannot be use to say answer (E) as well.

thankx fig, you are correct and i also corrected myself as well....

(1) 2x-2y = 1
x = y+ 1/2. x or y, both, could be either - or +.

(2) x/y >1.
x>y but both should be +ves.
x<y but both should be -ves.

togather:
if y = 0.5, x = 0.5+0.5 = 1 (and we have x/y = 1/0.5 = 2 which is greater than 1).
if y = -1, x = -0.5 (and we have x/y = 1/2 which is incorrect.) therefore, only x>y and only +ve values for x and y work.

2(x-y) = 1 => (x-y) = 1/2 ....... (b) From (a) (x-y) > 0 & from (b) (x-y) = 1/2

i.e 1/2 > 0 => 1 > 2 Not true...

Therefore C cannot be the answer.

your assertion in a is not correct.

if x/y > 1 then you cannot always say that x > y because x and y could be negative too

consider x = -6 and y = -3 x/y > 1 and x < y

You are missing statement 1 in which x>y
1=> x = y+1/2
For any value of y, x will always be greater than y.
Taking your example of y =-3, x = -3+1/2
x = -2.5
Hence x/y>1.
Therefore C.

2(x-y) = 1 => (x-y) = 1/2 ....... (b) From (a) (x-y) > 0 & from (b) (x-y) = 1/2

i.e 1/2 > 0 => 1 > 2 Not true...

Therefore C cannot be the answer.

your assertion in a is not correct.

if x/y > 1 then you cannot always say that x > y because x and y could be negative too

consider x = -6 and y = -3 x/y > 1 and x < y

You are missing statement 1 in which x>y 1=> x = y+1/2 For any value of y, x will always be greater than y. Taking your example of y =-3, x = -3+1/2 x = -2.5 Hence x/y>1. Therefore C.

you are missing the point

I am not disputing the answer (ie C). I was just pointing out that what haas_mba07 asserted (in red font above) is not correct .

ie just considering x/y > 1 , one cannot conclude that x > y.