Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

1 st)
2x-2y=1
x-y=1/2 insuff since x and y can be anything
x=1 and y=1/2 or x= -1/2 and y=-1
2) x/y >1 x and y may be both pos and both negative
-2/-1>1
E for me
_________________

1 st) 2x-2y=1 x-y=1/2 insuff since x and y can be anything x=1 and y=1/2 or x= -1/2 and y=-1 2) x/y >1 x and y may be both pos and both negative -2/-1>1 E for me

E for me too ........ used the exact methodology and numbers

(1) 2x-2y = 1
x = y+ 1/2. x or y, both, could be either - or +.

(2) x/y >1.
x>y but both should be +ves.
x<y but both should be -ves.

togather:
if y = 0.5, x = 1 (and we have x/y = 1/0.5 = 2 which is greater than1).
ok, if y = -0.5, x = 0 (and we have x/y = 0 which isn't greater than1).

(1) 2x-2y = 1 x = y+ 1/2. x or y, both, could be either - or +.

(2) x/y >1. x>y but both should be +ves. x<y but both should be -ves.

togather: if y = 0.5, x = 1 (and we have x/y = 1/0.5 = 2 which is greater than1). ok, if y = -0.5, x = 0 (and we have x/y = 0 which isn't greater than1).

So E is it.

Prof, we cannot take this exemple simply because this exemple is not respecting statment 2. It respects the line equation but not x/y > 1. So it cannot be use to say answer (E) as well.

Prof, we cannot take this exemple simply because this exemple is not respecting statment 2. It respects the line equation but not x/y > 1. So it cannot be use to say answer (E) as well.

thankx fig, you are correct and i also corrected myself as well....

(1) 2x-2y = 1
x = y+ 1/2. x or y, both, could be either - or +.

(2) x/y >1.
x>y but both should be +ves.
x<y but both should be -ves.

togather:
if y = 0.5, x = 0.5+0.5 = 1 (and we have x/y = 1/0.5 = 2 which is greater than 1).
if y = -1, x = -0.5 (and we have x/y = 1/2 which is incorrect.) therefore, only x>y and only +ve values for x and y work.

2(x-y) = 1 => (x-y) = 1/2 ....... (b) From (a) (x-y) > 0 & from (b) (x-y) = 1/2

i.e 1/2 > 0 => 1 > 2 Not true...

Therefore C cannot be the answer.

your assertion in a is not correct.

if x/y > 1 then you cannot always say that x > y because x and y could be negative too

consider x = -6 and y = -3 x/y > 1 and x < y

You are missing statement 1 in which x>y
1=> x = y+1/2
For any value of y, x will always be greater than y.
Taking your example of y =-3, x = -3+1/2
x = -2.5
Hence x/y>1.
Therefore C.

2(x-y) = 1 => (x-y) = 1/2 ....... (b) From (a) (x-y) > 0 & from (b) (x-y) = 1/2

i.e 1/2 > 0 => 1 > 2 Not true...

Therefore C cannot be the answer.

your assertion in a is not correct.

if x/y > 1 then you cannot always say that x > y because x and y could be negative too

consider x = -6 and y = -3 x/y > 1 and x < y

You are missing statement 1 in which x>y 1=> x = y+1/2 For any value of y, x will always be greater than y. Taking your example of y =-3, x = -3+1/2 x = -2.5 Hence x/y>1. Therefore C.

you are missing the point

I am not disputing the answer (ie C). I was just pointing out that what haas_mba07 asserted (in red font above) is not correct .

ie just considering x/y > 1 , one cannot conclude that x > y.