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Area: Do you see a correct answer choice here?

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Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 07:43
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What is the area of a square that has a diagonal of length 10?

A. 5
B. 10
C. 20
D. 40
E. 45

Source: Cliff's GMAT
[Reveal] Spoiler: OA

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Re: Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 07:54
Expert's post
gmatpapa wrote:
What is the area of a square that has a diagonal of length 10?

A. 5
B. 10
C. 20
D. 40
E. 45

Source: Cliff's GMAT


\(area_{square}=side^2=\frac{diagonal^2}{2}\): so A to be the answer either option A should read 50 instead of 5 or diagonal should be \(\sqrt{10}\) instead of 10.
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Director
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Status: Up again.
Joined: 31 Oct 2010
Posts: 543
Concentration: Strategy, Sustainability
GMAT 1: 710 Q48 V40
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Followers: 17

Kudos [?]: 169 [0], given: 75

Re: Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 08:02
Bunuel wrote:
gmatpapa wrote:
What is the area of a square that has a diagonal of length 10?

A. 5
B. 10
C. 20
D. 40
E. 45

Source: Cliff's GMAT


\(area_{square}=side^2=\frac{diagonal^2}{2}\): so A to be the answer either option A should read 50 instead of 5 or diagonal should be \(\sqrt{10}\) instead of 10.


Yes. Answer quite clearly should be 50.

Does this OE make sense to you:
From the relationship that exists in a right triangle, we see that the sides of the square
must equal the square root of 5. Thus the area of the square is 5

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Re: Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 08:07
Expert's post
gmatpapa wrote:
Bunuel wrote:
gmatpapa wrote:
What is the area of a square that has a diagonal of length 10?

A. 5
B. 10
C. 20
D. 40
E. 45

Source: Cliff's GMAT


\(area_{square}=side^2=\frac{diagonal^2}{2}\): so A to be the answer either option A should read 50 instead of 5 or diagonal should be \(\sqrt{10}\) instead of 10.


Yes. Answer quite clearly should be 50.

Does this OE make sense to you:
From the relationship that exists in a right triangle, we see that the sides of the square
must equal the square root of 5. Thus the area of the square is 5


As OE says that \(side=\sqrt{5}\) then there must be the second case I suggested: diagonal should be \(\sqrt{10}\) instead of 10.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis ; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) ; 12. Tricky questions from previous years.

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

GMAT Club Premium Membership - big benefits and savings

Director
Director
avatar
Status: Up again.
Joined: 31 Oct 2010
Posts: 543
Concentration: Strategy, Sustainability
GMAT 1: 710 Q48 V40
GMAT 2: 740 Q49 V42
Followers: 17

Kudos [?]: 169 [0], given: 75

Re: Area: Do you see a correct answer choice here? [#permalink] New post 03 Feb 2011, 08:15
Yep. Quite correct as diagonal = \(sqrt2\)*side. So side will be \(\frac{sqrt10}{sqrt2}\)= \(sqrt 5\). And area will be \(side^2= 5\).
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Re: Area: Do you see a correct answer choice here? [#permalink] New post 05 Feb 2011, 04:03
i did a bit different - x^2+x^2 = 10^2
x=squrt2*5
x^2 = 2*25 = 50
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Director
Director
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Status: Up again.
Joined: 31 Oct 2010
Posts: 543
Concentration: Strategy, Sustainability
GMAT 1: 710 Q48 V40
GMAT 2: 740 Q49 V42
Followers: 17

Kudos [?]: 169 [0], given: 75

Re: Area: Do you see a correct answer choice here? [#permalink] New post 05 Feb 2011, 05:01
144144 wrote:
i did a bit different - x^2+x^2 = 10^2
x=squrt2*5
x^2 = 2*25 = 50


Its essentially the same thing if you look at it. Diagonal= \(sqrt2\)*side is arrived using the same formula that you have used. (Pythagoras theorem)
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Re: Area: Do you see a correct answer choice here? [#permalink] New post 05 Feb 2011, 09:23
ye, i noticed it after i posted. thanks.
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Re: Area: Do you see a correct answer choice here?   [#permalink] 05 Feb 2011, 09:23
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