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# Arithmetic4

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Manager
Joined: 19 Aug 2009
Posts: 79
Followers: 1

Kudos [?]: 174 [0], given: 46

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07 Nov 2009, 02:06
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Question Stats:

100% (03:22) correct 0% (00:00) wrong based on 1 sessions

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The total salary of A,B ,C is $444. If they spend 80%,85% and 75% of their salaries respectively, their savings are 7:6:9. Then salary of B is 1. 140 2. 160 3. 144 Senior Manager Joined: 18 Aug 2009 Posts: 303 Followers: 3 Kudos [?]: 205 [0], given: 9 Re: Arithmetic4 [#permalink] ### Show Tags 07 Nov 2009, 03:19 B. 160 ? Went by brute force (5+mins), must be some better way to do it... B=444 - (A+C) A's saving = 20% = (1/5)A B's saving = (3/20)B C's saving = (1/4)C Using the given ration to get A & C in B form: [(1/5)A]/[(3/20)B]=7/6 => A=(7/8)B Similarly C=(9/10)B So B= 444 - [(7/8)B + (9/10)B] Solving this equation; B=160 Intern Affiliations: CA - India Joined: 27 Oct 2009 Posts: 45 Location: India Schools: ISB - Hyderabad, NSU - Singapore Followers: 19 Kudos [?]: 608 [1] , given: 5 Re: Arithmetic4 [#permalink] ### Show Tags 07 Nov 2009, 07:04 1 This post received KUDOS Spendings of A, B and C are 80%, 85% and 75%. so we can derive that total spending to be 80% of the total. Total salary is 444, which means total spending (80%) is approx.$ 355.2 and savings is $88.8. B's share in it is 6/22 or approx.$ 24 which 15% of his earning. Hence B's salary should be $160. Is this right OA? Manager Joined: 17 Aug 2009 Posts: 235 Followers: 5 Kudos [?]: 173 [0], given: 25 Re: Arithmetic4 [#permalink] ### Show Tags 10 Nov 2009, 00:30 Good one Kalpesh Nice way Agree with 160$
Manager
Joined: 23 Jun 2009
Posts: 155
Followers: 1

Kudos [?]: 9 [0], given: 9

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11 Nov 2009, 21:32
Spendings of A, B and C are 80%, 85% and 75%. so we can derive that total spending to be 80% of the total.

Total salary is 444, which means total spending (80%) is approx. $355.2 and savings is$ 88.8. B's share in it is 6/22 or approx. $24 which 15% of his earning. Hence B's salary should be$ 160.

Is this right OA?

I also used approximation but of a different kind. I assumed 15% of B's salary= Multiple of 6 in order to get integer values for savings of A&B&C. Got to option "160" and worked backwards to verify if all the salaries added up to 444
Manager
Joined: 10 Sep 2009
Posts: 119
Followers: 3

Kudos [?]: 43 [0], given: 10

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12 Nov 2009, 03:06
Spendings of A, B and C are 80%, 85% and 75%. so we can derive that total spending to be 80% of the total.

Total salary is 444, which means total spending (80%) is approx. $355.2 and savings is$ 88.8. B's share in it is 6/22 or approx. $24 which 15% of his earning. Hence B's salary should be$ 160.

Is this right OA?

I guess that you are taking in this example the assumption that all salaries are almost the same...
Let's imagine salary A = 10$and salary C = 10$ ... you will have some troubles to find the good solution.

Even if this way is really smart, the assumption could kill you.
Re: Arithmetic4   [#permalink] 12 Nov 2009, 03:06
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