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As j increases from 135 to 136 [#permalink]
 08 Aug 2012, 09:23
Question Stats:
73% (02:05) correct
26% (01:06) wrong based on 3 sessions
As j increases from 135 to 136, which of the following must decrease? I. 1 - j^2II. j - j^2III. \frac{1}{j^2}(A) I only (B) II only (C) I and II (D) I and III (E) I, II and III Source: http://www.gmathacks.com
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Re: As j increases from 135 to 136 [#permalink]
08 Aug 2012, 11:23
Since as per Qs J is a positive no. We can try a pretty small no and check all options. Let say j=2 and it increase to 3 i) decrease from -3 to -8 ii) decrease from -2 to -4 iii) decrease from 1/4 to 1/9 Answer: E
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Last edited by SOURH7WK on 08 Aug 2012, 12:13, edited 1 time in total.
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Re: As j increases from 135 to 136 [#permalink]
08 Aug 2012, 11:52
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metallicafan wrote: As j increases from 135 to 136, which of the following must decrease? I. 1 - j^2II. j - j^2III. \frac{1}{j^2}(A) I only (B) II only (C) I and II (D) I and III (E) I, II and III Source: http://www.gmathacks.comI y = 1 - x^2 is the equation of a downward parabola, intercepting the x axis at -1 and 1. So, far away from the roots, the values of the function are decreasing as x increases. YES II y=x-x^2 is also the equation of a downward parabola, roots 0 and 1. Again, far away from the roots, the values of the function are decreasing as x increases. YES III Definitely decreases, the larger the denominator, the smaller the value of the fraction. YES Answer E
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Re: As j increases from 135 to 136 [#permalink]
08 Aug 2012, 11:53
SOURH7WK wrote: Since as per Qs J is a positive no. We can try a pretty small no and check all options.
Let say j=2 and it increase to 3
i) decrease from -3 to -8
ii) decrease from -2 to -4
iii) decrease from 1/4 to 1/9
Answer: C The values of j are defined: 135 and 136!
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Re: As j increases from 135 to 136 [#permalink]
08 Aug 2012, 15:05
Ouch! I didn't notice it was a function.  Thank you!
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Re: As j increases from 135 to 136 [#permalink]
27 Aug 2012, 09:13
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take a smaller number like 2 and 3 and solve. We get the ans to be E
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Re: As j increases from 135 to 136 [#permalink]
29 Aug 2012, 08:04
It can be solved using values (1) 1- j^2 : Obviously if j increases, value of J^2 will increase. This will in turn decrease the value of 1- j^2(2) J-J^2 = J*(1-J)when J=135, we get -135*134 when J=136, we get -136*135 Therefore, from the values we can easily see it is decreasing. (3) 1/J^2 : as the denominator decrease, so the result will decrease. As in all three cases, values decrease the answer is E
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Re: As j increases from 135 to 136 [#permalink]
10 Dec 2012, 01:31
I. 1-j^2 Of course, a larger portion is taken from 1. Definitely the value will decrease.
II. j - j^2 I thought of smaller positive consecutive numbers such as 2 and 3. -2 vs. -6 shows a decrease.
\frac{1}{j^2} The larger the denominater, the smaller the fraction.
Answer: I,II, III or (E)
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As j increases from 135 to 136, which of following must [#permalink]
02 Mar 2013, 22:41
As j increases from 135 to 136, which of the following must decrease?I. 1 - j^2II. j - j^2III. \frac{1}{j^2}(A) I only (B) II only (C) I and II (D) I and III (E) I, II and III Source: Gmat Hacks 1800
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Re: As j increases from 135 to 136, which of following must [#permalink]
03 Mar 2013, 00:04
I. As j increases, j^2 will increase too. Therefore 1-j^2 will decrease. II. j-j^2 = j(1-j). As j increases, 1-j will decrease and be negative. Multiplied by the increased j, this gives us a more negative figure. Therefore j-j^2 will decrease too. III. Simple reciprocal. As j increases from 135 to 136, 1/j^2 is bound to decrease E it is.
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Re: As j increases from 135 to 136, which of following must [#permalink]
03 Mar 2013, 01:03
megafan wrote: As j increases from 135 to 136, which of the following must decrease?
I. 1 - j^2
II. j - j^2
III. \frac{1}{j^2}
(A) I only
(B) II only
(C) I and II
(D) I and III
(E) I, II and III
Source: Gmat Hacks 1800 Assume j increases from 2 to 4 I. 1 - j^2 1- 2^2 = 1-4 = -3 1- 3^2 = 1-9 = -8 So this is true II. j - j^2 2- 2^2 = 2-4 = -2 3- 3^2 = 3-9 = -6 So this is true III. \frac{1}{j^2} \frac{1}{2^2} = 0.25 \frac{1}{4^2} = 0.0XX So this is true Therefor , E
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Re: As j increases from 135 to 136, which of following must [#permalink]
03 Mar 2013, 03:07
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Re: As j increases from 135 to 136, which of following must
[#permalink]
03 Mar 2013, 03:07
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