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# As part of a game, four people each must secretly choose an

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CEO
Joined: 15 Aug 2003
Posts: 3467
Followers: 61

Kudos [?]: 718 [0], given: 781

As part of a game, four people each must secretly choose an [#permalink]  23 Sep 2003, 13:54
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As part of a game, four people each must secretly choose an integer between 1 and 4, inclusive. What is the approximate likelihood that all four people will choose different numbers?
Intern
Joined: 16 Jul 2003
Posts: 32
Followers: 0

Kudos [?]: 0 [0], given: 0

Total choices possible = 4^4.

All 4 select different number = 4!

Hence, likelihood of all 4 selecting different nos. = 4!/4^4
= 3/32.
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