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# At 10th birthday party, X received 30 candies. He was then

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SVP
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At 10th birthday party, X received 30 candies. He was then [#permalink]

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07 Nov 2005, 19:55
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At 10th birthday party, X received 30 candies. He was then forced by his parents to give away at least 30% of those candies to his playmates, one to each playmate. If more than a third of the playmates ate the candies that he gave them while the rest gave them back to the child, what is the greatest number of candies that the child could have ended up with?

(A) 23
(B) 24
(C) 26
(D) 27
(E) 29
Director
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07 Nov 2005, 19:56
All of you took some same test today or what?! -
http://www.gmatclub.com/phpbb/viewtopic.php?t=22667
SVP
Joined: 05 Apr 2005
Posts: 1731
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Kudos [?]: 58 [0], given: 0

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07 Nov 2005, 19:58
gsr wrote:
All of you took some same test today or what?! -
http://www.gmatclub.com/phpbb/viewtopic.php?t=22667

how do you know which question is where? posted when?
Director
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07 Nov 2005, 20:02
HIMALAYA wrote:
gsr wrote:
All of you took some same test today or what?! -
http://www.gmatclub.com/phpbb/viewtopic.php?t=22667

how do you know which question is where? posted when?

Just saw 5 mins back. It is all 3 or 4 posts below this!!
Director
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07 Nov 2005, 23:54
C ...

gave 30% of total that is 9

more then 30% of playmates means more than 3 playmates ...so for child to get maximum back ...only 4 plamates ate the candies and 5 gave back ...

so child will end with 21 + 5 = 26

what is OA ..?

Senior Manager
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08 Nov 2005, 22:43
If I understand the question correctly....

Playmates = 0.3*30 = 9

Child|leftover = 21

Playmates|eat > 1/3 * 9 = 3

If assume that the Playmate ate 4 pieces of candy, then 5 pieces will be returned to the child.

Child|Total = 21 + 5 = 26
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09 Nov 2005, 23:44
30% of 30 = 9. So X has 21 candies now. 1/3 of 9 = 3 since more than a third ate, implies atleast 4 playmate ate. So the remaining is 5 which was given back. 21 + 5 = 26. Hence C.
Re: PS: Birthday   [#permalink] 09 Nov 2005, 23:44
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