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At a bakery, all donuts are priced equally and all bagels

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At a bakery, all donuts are priced equally and all bagels [#permalink]  06 Dec 2012, 03:17
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At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90. (2) At the bakery, the price of a donut is$0.15 less than the price of a bagel.
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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]  06 Dec 2012, 03:22
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At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

Say the price of a donut is $x and the price of a bagel is$y. We need to find the value of 5x+3y.

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90 --> given that 10x+6y=$12.9 --> reduce by 2: 5x+3y=$12.9/2. Sufficient. (2) At the bakery, the price of a donut is$0.15 less than the price of a bagel --> given that x=y-0.15 --> 5x+3y=5(y-0.15)+3y. We need the value of y (or x). Not sufficient.

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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]  06 Dec 2012, 03:23
Question asks for value of 5D + 3B.

1)10D + 6B = 12.9
5D + 3B = 12.9/2. Sufficient

2)We only have D = B - 0.15. Even after substitution of this in 5D + 3B we still have an unknown. Insufficient.

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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]  06 Dec 2012, 03:42
Expert's post
This is a question based on logic you can solve in at most 20 seconds, without any calculation.

A clearly is the answer .
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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]  10 Jan 2014, 08:17
At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90. (2) At the bakery, the price of a donut is$0.15 less than the price of a bagel.

We are given 5*D + 3*B = TC, so what's TC?

1) Look carefully: This simply tells us what 2TC is, so in other words it tells us what 2(5*D + 3*B) is. just take half the result and you've solved the question.

2) This tells us that 5*(B - 0.15) + 3*B = TC, but we have two unknowns and one equation, so 2 is not sufficient.

We go with A.
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Donut and bagel at bakery question [#permalink]  10 Jul 2014, 09:10
At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90 (2) At the bakery, the price of a donut is$0.15 less than the price of a bagel.

I understand 1) is sufficient. But I'm not understanding why 2) is insufficient. If you let price of donut be x, then price of bagel is x+0.15. Therefore 10x + 6(x + 0.15) = 12.90. Solve that and get a value for x and obviously x + 0.15.

Am I missing something obvious?
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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]  10 Jul 2014, 09:13
Expert's post
JaredL wrote:
At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90 (2) At the bakery, the price of a donut is$0.15 less than the price of a bagel.

I understand 1) is sufficient. But I'm not understanding why 2) is insufficient. If you let price of donut be x, then price of bagel is x+0.15. Therefore 10x + 6(x + 0.15) = 12.90. Solve that and get a value for x and obviously x + 0.15.

Am I missing something obvious?

Merging similar topics. Please refer to the discussion above.

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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]  20 Jul 2015, 18:02
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Re: At a bakery, all donuts are priced equally and all bagels   [#permalink] 20 Jul 2015, 18:02
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