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# At a bakery, all donuts are priced equally and all bagels

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At a bakery, all donuts are priced equally and all bagels [#permalink]

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06 Dec 2012, 04:17
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At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90. (2) At the bakery, the price of a donut is$0.15 less than the price of a bagel.
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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]

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06 Dec 2012, 04:22
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At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

Say the price of a donut is $x and the price of a bagel is$y. We need to find the value of 5x+3y.

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90 --> given that 10x+6y=$12.9 --> reduce by 2: 5x+3y=$12.9/2. Sufficient. (2) At the bakery, the price of a donut is$0.15 less than the price of a bagel --> given that x=y-0.15 --> 5x+3y=5(y-0.15)+3y. We need the value of y (or x). Not sufficient.

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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]

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11 Oct 2016, 16:50
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At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90. (2) At the bakery, the price of a donut is$0.15 less than the price of a bagel.

We are given that all donuts are priced equally and all bagels are priced equally and need to determine the total price of 5 donuts and 3 bagels. Let’s start by defining some variables.

D = the price per donut

B = the price per bagel

Thus we need to determine: 5D + 3B = ?

Statement One Alone:

At the bakery, the total price of 10 donuts and 6 bagels is $12.90. Using the information in statement one, we can create the following equation: 10D + 6B = 12.90 We can simplify the equation by dividing the entire equation by 2. 5D + 3B = 6.45 Thus, the price for 5 donuts and 3 bagels is$6.45. Statement one alone is sufficient to answer the question. We can eliminate answer choices B, C, and E.

Statement Two Alone:

(2) At the bakery, the price of a donut is $0.15 less than the price of a bagel. I understand 1) is sufficient. But I'm not understanding why 2) is insufficient. If you let price of donut be x, then price of bagel is x+0.15. Therefore 10x + 6(x + 0.15) = 12.90. Solve that and get a value for x and obviously x + 0.15. Am I missing something obvious? Math Expert Joined: 02 Sep 2009 Posts: 35249 Followers: 6628 Kudos [?]: 85426 [0], given: 10236 Re: At a bakery, all donuts are priced equally and all bagels [#permalink] ### Show Tags 10 Jul 2014, 10:13 JaredL wrote: At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery? (1) At the bakery, the total price of 10 donuts and 6 bagels is$12.90

(2) At the bakery, the price of a donut is \$0.15 less than the price of a bagel.

I understand 1) is sufficient. But I'm not understanding why 2) is insufficient. If you let price of donut be x, then price of bagel is x+0.15. Therefore 10x + 6(x + 0.15) = 12.90. Solve that and get a value for x and obviously x + 0.15.

Am I missing something obvious?

Merging similar topics. Please refer to the discussion above.

All OG 13 questions with solutions are here: the-official-guide-quantitative-question-directory-143450.html

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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]

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20 Jul 2015, 19:02
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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]

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19 Sep 2015, 14:49
I found the answer using both of the statements.

1) 10d + 5b = 12.90
2) d = b - 0.15
10(b-0.15)+6b=12.90
10b-1.5+6b=12.90
16b=14.4
b=0.9
[substitute for b in 2nd equation]
d=0.9-0.15=0.75
5(0.75)+3(0.9)=6.45, which is equal to 12.90(0.5)
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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]

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10 Oct 2016, 10:54
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: At a bakery, all donuts are priced equally and all bagels   [#permalink] 10 Oct 2016, 10:54
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