At a bakery, all donuts are priced equally and all bagels

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At a bakery, all donuts are priced equally and all bagels [#permalink]

06 Dec 2012, 04:17

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At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90.
(2) At the bakery, the price of a donut is $0.15 less than the price of a bagel.

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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]

06 Dec 2012, 04:22

At a bakery, all donuts are priced equally and all bagels are priced equally. What is the total price of 5 donuts and 3 bagels at the bakery?

Say the price of a donut is $x and the price of a bagel is $y. We need to find the value of 5x+3y.

(1) At the bakery, the total price of 10 donuts and 6 bagels is $12.90 --> given that 10x+6y=$12.9 --> reduce by 2: 5x+3y=$12.9/2. Sufficient.

(2) At the bakery, the price of a donut is $0.15 less than the price of a bagel --> given that x=y-0.15 --> 5x+3y=5(y-0.15)+3y. We need the value of y (or x). Not sufficient.

Answer: A.
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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]

06 Dec 2012, 04:23

Question asks for value of 5D + 3B.

1)10D + 6B = 12.9
5D + 3B = 12.9/2. Sufficient

2)We only have D = B - 0.15. Even after substitution of this in 5D + 3B we still have an unknown. Insufficient.

Answer is A.
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Re: At a bakery, all donuts are priced equally and all bagels [#permalink]

06 Dec 2012, 04:42

This is a question based on logic you can solve in at most 20 seconds, without any calculation.

A clearly is the answer .
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Re: At a bakery, all donuts are priced equally and all bagels [#permalink] 06 Dec 2012, 04:42

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At a bakery, all donuts are priced equally and all bagels

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At a bakery, all donuts are priced equally and all bagels

At a bakery, all donuts are priced equally and all bagels

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