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At a certain bakery, each roll costs r cents and each [#permalink]
18 Dec 2005, 17:08
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Difficulty:
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Question Stats:
72% (01:50) correct
28% (01:00) wrong based on 121 sessions
At a certain bakery, each roll costs r cents and each doughnut costs d cents. If Alfredo bought rolls and doughnuts at the bakery, how many cents did he pay for each roll?
(1) Alfredo paid $5.00 for 8 rolls and 6 doughnuts (2) Alfredo would have paid $ 10.00 if he had bought 16 rolls and 12 doughnuts
Re: At a certain bakery, each roll costs r cents and each [#permalink]
18 Dec 2005, 17:11
This is a typical GMAT trap. YOu might have seen my earlier post about picking numbers for DS. In general, two equations in two unknowns can be solved to get a unique (one) solution except when the two equations are the same. If you divide the information in statement 2, you get statemetn 1. So, statemetn 2 is not giving you any new information. Hence, the answer should be E.
Re: At a certain bakery, each roll costs r cents and each [#permalink]
19 Dec 2005, 00:51
joemama142000 wrote:
At a certain bakery, each roll costs r cents and each doughnut costs d cents. If Alfredo bought rolls and doughnuts at the bakery, how many cents did he pay for each roll?
1) Alfredo paid $5.00 for 8 rolls and 6 doughnuts
2) Alfredo would have paid $ 10.00 if he had bought 16 rolls and 12 doughnuts
From stmt1 we get 8r+6d = 5
From stmt2 we get 16r + 12d = 10
Stmt1 * 2 = stmt 2, and we will not be able to solve this equen. So my answer is E.
Re: At a certain bakery, each roll costs r cents and each [#permalink]
03 Jan 2015, 09:42
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Re: At a certain bakery, each roll costs r cents and each [#permalink]
05 Jan 2015, 03:12
Expert's post
At a certain bakery, each roll costs r cents and each doughnut costs d cents. If Alfredo bought rolls and doughnuts at the bakery, how many cents did he pay for each roll?
Let \(r\) be the price of rolls in cents and \(d\) be the price of doughnuts in cents. Note that \(r\) and \(d\) must be an integers. Q: \(r=?\)
(1) Alfredo paid $5.00 for 8 rolls and 6 doughnuts --> \(8r+6d=500\) --> \(4r+3d=250\). Multiple solutions are possible, for instance: \(r=25\) and \(d=50\) OR \(r=10\) and \(d=70\). Not sufficient.
(2) Alfredo would have paid $ 10.00 if he had bought 16 rolls and 12 doughnuts --> \(16r+12d=1000\) --> \(4r+3d=250\). The same. Not sufficient.
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