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At a certain company, 25 percent of the employees are male

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At a certain company, 25 percent of the employees are male [#permalink] New post 05 Jan 2011, 17:37
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At a certain company, 25 percent of the employees are male and 50 percent of the
employees are sales staff. What is the number of employees at this company?

(1) Exactly 7 of the employees at the company are males who are sales staff.
(2) There are 16 more female employees than male employees at the company.
[Reveal] Spoiler: OA

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Re: At a certain company, 25 percent [#permalink] New post 05 Jan 2011, 18:23
Great question. Initially threw me off and I wasted a lot of time because I thought was a percent/sets question but it's just alegbra.

1) Exactly 7 of the employees at the company are males who are sales staff.
This does not give us information about males not on the sales staff, women on sales staff etc. Not sufficient
2) There are 16 more female employees than male employees at the company
This gives us:
w = m + 16
.75total = w
.25total = m
Substitute into first equation you have
.75total = .25total + 16 Sufficient
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Re: At a certain company, 25 percent of [#permalink] New post 05 Jan 2011, 23:28
ajit257 wrote:
At a certain company, 25 percent of the employees are male and 50 percent of the
employees are sales staff. What is the number of employees at this company?

(1) Exactly 7 of the employees at the company are males who are sales staff.
(2) There are 16 more female employees than male employees at the company.


Let M be number of males
Let S be number of sales staff

M=25%
S=50%

1) M&S = 7
We cant find the total since we know nothing about what percentage of total employees is 7, and that just males and sales staff may not make up the entire employee set

2) F = M+16
and we know M is 25%
So F is 75%
3M = M + 16
M=8
Total employees=M+F=32

Sufficient --> Answer is (b)
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Re: At a certain company, 25 percent of [#permalink] New post 06 Jan 2011, 00:17
Ans B - Statement B Alone but not A alone is sufficient.

Statement A : We are not sure If the number of males is just 7,it could be more, not sufficient.

Male 25 %, Female 75 %
Females are 16 more than the males

Also 75 %- 25 % = 16, So we can have 16 = 50 % of the total

16:50 , then 16*100/50 = 32.
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Re: At a certain company, 25 percent of [#permalink] New post 06 Jan 2011, 00:21
Ans B - Statement B Alone but not A alone is sufficient.

Male 25 %, Female 75 %

Statement A : We are not sure If the number of males is just 7,it could be more, not sufficient.

Statement B :

Females are 16 more than the males

Also 75 %- 25 % = 16, So we can have 16 = 50 % of the total

16:50 , then 16*100/50 = 32. Sufficient.

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Re: At a certain company, 25 percent of [#permalink] New post 06 Jan 2011, 00:56
Can this problem be solved in a "Groups vs. Subgroups" table?

If so - how so?

Bunuel...?
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Re: At a certain company, 25 percent of   [#permalink] 06 Jan 2011, 00:56
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