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At a certain company, a test was given to a group of men and [#permalink]
 02 Jun 2012, 00:28
Question Stats:
46% (01:58) correct
54% (01:12) wrong based on 50 sessions
At a certain company, a test was given to a group of men and women seeking for promotions. If the average (artihmetic mean) score for the group was 80, was the average score for the women more than 85? (1) The average score for the men was less than 75. (2) The group consisted of more men than women. Would someone please help me out with this question. I got no clue combining st.1 and 2 and the output of it.
Last edited by Bunuel on 02 Jun 2012, 05:26, edited 1 time in total.
Edited the question
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Re: DS help needed!! [#permalink]
02 Jun 2012, 02:03
rajman41 wrote: 1) The average score for the group was less than 75.
Is the question correct? What is statement 1 trying to say?
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Re: DS help needed!! [#permalink]
02 Jun 2012, 02:47
At a certain company, a test was given to a group of men and women seeking promotions. If the average(artihmetic mean) score for the group was 80, was the average score for the women greater than 85?
1) The average score for the men was less than 75.
2) The group consisted of more men than women.
Thank you!!
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Re: DS help needed!! [#permalink]
02 Jun 2012, 04:51
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rajman41 wrote: At a certain company, a test was given to a group of men and women seeking promotions. If the average(artihmetic mean) score for the group was 80, was the average score for the women greater than 85?
1) The average score for the men was less than 75.
2) The group consisted of more men than women.
Thank you!! Clearly both statement by itself are insufficient. Let us say the group were equal. Then if Men(x) average was 75, then women(x) average would be 85 As 75x + 85x = 80(2x) IF Men were more (lets say x+1) and average of women's score was W 75(x+1) + Wx = 80(2x+1) 75x + 75 + Wx = 160x + 80 Wx - 85x = 5 x(W-85) = 5 As X cannot be zero or negetive W-85>0 or W>85 BOth sufficient
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Re: At a certain company, a test was given to a group of men and [#permalink]
02 Jun 2012, 05:45
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You can solve this question without any algebra. At a certain company, a test was given to a group of men and women seeking for promotions. If the average (artihmetic mean) score for the group was 80, was the average score for the women more than 85?(1) The average score for the men was less than 75. Since the average score for the group was 80 then the average score for women must be more than 80, but we don't know whether it's more than 85. Not sufficient. (2) The group consisted of more men than women. Clearly insufficient. (1)+(2) From (1) we have that the distance between the average score for the men and the average score for the whole group is more than 5 and from (2) we have that there are more men than women. Now, in order to compensate that difference and to make the average for the whole group 80 the average of the smaller group (women) must be further from 80 than the average for the larger group (men), so the average score for the women must be more than 85. Sufficient. Answer: C. Hope it's clear.
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Re: At a certain company, a test was given to a group of men and [#permalink]
02 Jun 2012, 07:02
This is so far the clear and precise explanation, thanks Bunuel!!
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Re: At a certain company, a test was given to a group of men and [#permalink]
22 Dec 2012, 05:12
Let number of men and women be m and w.
[m*Avg(m) + w*Avg(w)]/[m+w] = 80 ---from the problem statement
or, m*Avg(m) + w*Avg(w) = 80m + 80w
From 1st option, Avg(m) < 75
substitute this in the equation of problem statement:
75m + w*Avg(w) > 80m + 80w
or w*Avg(w) > 5m + 80w
or Avg(w) > 5m/w + 80 ----- (1)
this isn't sufficient.
From 2nd statement:
m>w
this means, m/w > 1
substitute this in eq (1):
Avg(w) > 5 + 80
or Avg(w) > 85
So, both statement together can answer the problem. Hence, C
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Re: At a certain company, a test was given to a group of men and [#permalink]
28 Dec 2012, 07:03
Stem : (Am + Aw) / (Nm + Nw) = 80Where is average and n is number This is a weighted average problem, where we are asked to find whether Aw>85 Statement one I shall use the see-saw method 75----------------------80---------------------85
(5) (5)Nw:Nm = 5:5 = 1:1Hence we can see that for Aw=85, number of men and women should be equal. We can conclude that since we want Aw>85, Nw> Nm.Since we are not given this info. Insuff. (2) Clearly Insuff (1) + (2) together Bingo! we have exactly what we need Hence Suff
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Re: At a certain company, a test was given to a group of men and [#permalink]
20 Feb 2013, 23:29
Bunuel wrote: You can solve this question without any algebra.
At a certain company, a test was given to a group of men and women seeking for promotions. If the average (artihmetic mean) score for the group was 80, was the average score for the women more than 85?
(1) The average score for the men was less than 75. Since the average score for the group was 80 then the average score for women must be more than 80, but we don't know whether it's more than 85. Not sufficient.
(2) The group consisted of more men than women. Clearly insufficient.
(1)+(2) From (1) we have that the distance between the average score for the men and the average score for the whole group is more than 5 and from (2) we have that there are more men than women. Now, in order to compensate that difference and to make the average for the whole group 80 the average of the smaller group (women) must be further from 80 than the average for the larger group (men), so the average score for the women must be more than 85. Sufficient.
Answer: C.
Hope it's clear. Once again a wonderful explanation by the best. Bunuel makes me wonder how did u became so good at all this problems.
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Re: At a certain company, a test was given to a group of men and
[#permalink]
20 Feb 2013, 23:29
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