At a certain company, a test was given to a group of men and : GMAT Data Sufficiency (DS)
Check GMAT Club App Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 11 Dec 2016, 02:15

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# At a certain company, a test was given to a group of men and

Author Message
TAGS:

### Hide Tags

Intern
Joined: 16 Feb 2012
Posts: 27
GPA: 3.57
Followers: 0

Kudos [?]: 53 [2] , given: 0

At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

01 Jun 2012, 23:28
2
KUDOS
37
This post was
BOOKMARKED
00:00

Difficulty:

55% (hard)

Question Stats:

60% (02:15) correct 40% (01:25) wrong based on 1192 sessions

### HideShow timer Statistics

At a certain company, a test was given to a group of men and women seeking for promotions. If the average (artihmetic mean) score for the group was 80, was the average score for the women more than 85?

(1) The average score for the men was less than 75.
(2) The group consisted of more men than women.

Would someone please help me out with this question. I got no clue combining st.1 and 2 and the output of it.
[Reveal] Spoiler: OA

Last edited by Bunuel on 02 Jun 2012, 04:26, edited 1 time in total.
Edited the question
Manager
Joined: 12 May 2012
Posts: 83
Location: India
Concentration: General Management, Operations
GMAT 1: 650 Q51 V25
GMAT 2: 730 Q50 V38
GPA: 4
WE: General Management (Transportation)
Followers: 2

Kudos [?]: 89 [4] , given: 14

### Show Tags

02 Jun 2012, 03:51
4
KUDOS
3
This post was
BOOKMARKED
rajman41 wrote:
At a certain company, a test was given to a group of men and women seeking promotions. If the average(artihmetic mean) score for the group was 80, was the average score for the women greater than 85?
1) The average score for the men was less than 75.
2) The group consisted of more men than women.

Thank you!!

Clearly both statement by itself are insufficient.

Let us say the group were equal.
Then if Men(x) average was 75, then women(x) average would be 85
As 75x + 85x = 80(2x)

IF Men were more (lets say x+1) and average of women's score was W
75(x+1) + Wx = 80(2x+1)
75x + 75 + Wx = 160x + 80
Wx - 85x = 5
x(W-85) = 5
As X cannot be zero or negetive
W-85>0
or W>85

BOth sufficient
Math Expert
Joined: 02 Sep 2009
Posts: 35951
Followers: 6867

Kudos [?]: 90129 [29] , given: 10418

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

02 Jun 2012, 04:45
29
KUDOS
Expert's post
23
This post was
BOOKMARKED
You can solve this question without any algebra.

At a certain company, a test was given to a group of men and women seeking for promotions. If the average (artihmetic mean) score for the group was 80, was the average score for the women more than 85?

(1) The average score for the men was less than 75. Since the average score for the group was 80 then the average score for women must be more than 80, but we don't know whether it's more than 85. Not sufficient.

(2) The group consisted of more men than women. Clearly insufficient.

(1)+(2) From (1) we have that the distance between the average score for the men and the average score for the whole group is more than 5 and from (2) we have that there are more men than women. Now, in order to compensate that difference and to make the average for the whole group 80 the average of the smaller group (women) must be further from 80 than the average for the larger group (men), so the average score for the women must be more than 85. Sufficient.

Hope it's clear.
_________________
Intern
Joined: 16 Feb 2012
Posts: 27
GPA: 3.57
Followers: 0

Kudos [?]: 53 [0], given: 0

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

02 Jun 2012, 06:02
This is so far the clear and precise explanation, thanks Bunuel!!
Intern
Joined: 25 Mar 2012
Posts: 23
Location: India
Concentration: Strategy, General Management
GMAT 1: 710 Q50 V36
GPA: 3.04
WE: Consulting (Computer Software)
Followers: 0

Kudos [?]: 12 [1] , given: 1

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

22 Dec 2012, 04:12
1
KUDOS
Let number of men and women be m and w.

[m*Avg(m) + w*Avg(w)]/[m+w] = 80 ---from the problem statement
or, m*Avg(m) + w*Avg(w) = 80m + 80w

From 1st option, Avg(m) < 75

substitute this in the equation of problem statement:
75m + w*Avg(w) > 80m + 80w
or w*Avg(w) > 5m + 80w
or Avg(w) > 5m/w + 80 ----- (1)
this isn't sufficient.
From 2nd statement:
m>w
this means, m/w > 1
substitute this in eq (1):
Avg(w) > 5 + 80
or Avg(w) > 85

So, both statement together can answer the problem. Hence, C
Manager
Joined: 24 Mar 2010
Posts: 81
Followers: 1

Kudos [?]: 54 [3] , given: 134

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

28 Dec 2012, 06:03
3
KUDOS
Stem :
$$(Am + Aw) / (Nm + Nw) = 80$$

Where is average and n is number
This is a weighted average problem, where we are asked to find whether Aw>85

Statement one

I shall use the see-saw method

$$75----------------------80---------------------85 (5) (5)$$
$$Nw:Nm = 5:5 = 1:1$$
Hence we can see that for$$Aw=85,$$ number of men and women should be equal.

We can conclude that since we want $$Aw>85, Nw> Nm.$$

Since we are not given this info. Insuff.

(2)
Clearly Insuff

(1) + (2) together

Bingo! we have exactly what we need

Hence Suff
_________________

- Stay Hungry, stay Foolish -

Manager
Joined: 05 Nov 2012
Posts: 71
Schools: Foster '15 (S)
GPA: 3.65
Followers: 1

Kudos [?]: 115 [0], given: 8

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

20 Feb 2013, 22:29
Bunuel wrote:
You can solve this question without any algebra.

At a certain company, a test was given to a group of men and women seeking for promotions. If the average (artihmetic mean) score for the group was 80, was the average score for the women more than 85?

(1) The average score for the men was less than 75. Since the average score for the group was 80 then the average score for women must be more than 80, but we don't know whether it's more than 85. Not sufficient.

(2) The group consisted of more men than women. Clearly insufficient.

(1)+(2) From (1) we have that the distance between the average score for the men and the average score for the whole group is more than 5 and from (2) we have that there are more men than women. Now, in order to compensate that difference and to make the average for the whole group 80 the average of the smaller group (women) must be further from 80 than the average for the larger group (men), so the average score for the women must be more than 85. Sufficient.

Hope it's clear.

Once again a wonderful explanation by the best. Bunuel makes me wonder how did u became so good at all this problems.
_________________

___________________________________________
Consider +1 Kudos if my post helped

Manager
Joined: 18 May 2012
Posts: 83
Concentration: Finance, Marketing
Followers: 6

Kudos [?]: 88 [2] , given: 21

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

01 Jul 2013, 09:50
2
KUDOS
How about using wt avg (differences) --
Let
men = m
women = w

St 1 --->
Suppose avg score for men is 74.99
Difference for women = +X
(-5.01)*m + (+X)*w = 0 (differences should cancel out)
we cannot deduce X

St 2 --->
m>w : clearly insufficient

-------------------------------------------------------------
Combining --
(-5.01)*m + (+X)*w = 0
X = (5.01 * m)/w; since m > w => m/w > 1 ; therefore X will be greater than 5
Thus women's average = 80 + (>5) i.e greater than 85
_________________

Focusing on apps..
|GMAT Debrief|TOEFL Debrief|

Intern
Joined: 02 Oct 2013
Posts: 12
Followers: 0

Kudos [?]: 3 [0], given: 1

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

06 Oct 2013, 10:31
Bunuel wrote:
You can solve this question without any algebra.

At a certain company, a test was given to a group of men and women seeking for promotions. If the average (artihmetic mean) score for the group was 80, was the average score for the women more than 85?

(1) The average score for the men was less than 75. Since the average score for the group was 80 then the average score for women must be more than 80, but we don't know whether it's more than 85. Not sufficient.

(2) The group consisted of more men than women. Clearly insufficient.

(1)+(2) From (1) we have that the distance between the average score for the men and the average score for the whole group is more than 5 and from (2) we have that there are more men than women. Now, in order to compensate that difference and to make the average for the whole group 80 the average of the smaller group (women) must be further from 80 than the average for the larger group (men), so the average score for the women must be more than 85. Sufficient.

Hope it's clear.

Hi Bunuel

Can you please explain why C is correct . I am finding it difficult to understand how the number of men and women helps to answer the question

Regards
Math Expert
Joined: 02 Sep 2009
Posts: 35951
Followers: 6867

Kudos [?]: 90129 [1] , given: 10418

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

06 Oct 2013, 10:42
1
KUDOS
Expert's post
DivyanshuRohatgi wrote:
Bunuel wrote:
You can solve this question without any algebra.

At a certain company, a test was given to a group of men and women seeking for promotions. If the average (arithmetic mean) score for the group was 80, was the average score for the women more than 85?

(1) The average score for the men was less than 75. Since the average score for the group was 80 then the average score for women must be more than 80, but we don't know whether it's more than 85. Not sufficient.

(2) The group consisted of more men than women. Clearly insufficient.

(1)+(2) From (1) we have that the distance between the average score for the men and the average score for the whole group is more than 5 and from (2) we have that there are more men than women. Now, in order to compensate that difference and to make the average for the whole group 80 the average of the smaller group (women) must be further from 80 than the average for the larger group (men), so the average score for the women must be more than 85. Sufficient.

Hope it's clear.

Hi Bunuel

Can you please explain why C is correct . I am finding it difficult to understand how the number of men and women helps to answer the question

Regards

The average score for the men is 75.
The average score for the women is x.
The average score for the group is 80.

There are more men than women.

Now, ask yourself if x is less than 85, how can the average be 80?
_________________
Intern
Joined: 02 Oct 2013
Posts: 12
Followers: 0

Kudos [?]: 3 [0], given: 1

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

06 Oct 2013, 10:48
Bunuel wrote:
DivyanshuRohatgi wrote:
Bunuel wrote:
You can solve this question without any algebra.

At a certain company, a test was given to a group of men and women seeking for promotions. If the average (arithmetic mean) score for the group was 80, was the average score for the women more than 85?

(1) The average score for the men was less than 75. Since the average score for the group was 80 then the average score for women must be more than 80, but we don't know whether it's more than 85. Not sufficient.

(2) The group consisted of more men than women. Clearly insufficient.

(1)+(2) From (1) we have that the distance between the average score for the men and the average score for the whole group is more than 5 and from (2) we have that there are more men than women. Now, in order to compensate that difference and to make the average for the whole group 80 the average of the smaller group (women) must be further from 80 than the average for the larger group (men), so the average score for the women must be more than 85. Sufficient.

Hope it's clear.

Hi Bunuel

Can you please explain why C is correct . I am finding it difficult to understand how the number of men and women helps to answer the question

Regards

The average score for the men is 75.
The average score for the women is x.
The average score for the group is 80.

There are more men than women.

Now, ask yourself if x is less than 85, how can the average be 80?

Thanxs for the explanation
Current Student
Joined: 10 Nov 2013
Posts: 20
Location: United States
Concentration: Healthcare, Strategy
WE: Information Technology (Health Care)
Followers: 1

Kudos [?]: 12 [0], given: 130

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

02 Dec 2013, 21:41
rohanGmat wrote:
How about using wt avg (differences) --
Let
men = m
women = w

St 1 --->
Suppose avg score for men is 74.99
Difference for women = +X
(-5.01)*m + (+X)*w = 0 (differences should cancel out)
we cannot deduce X

St 2 --->
m>w : clearly insufficient

-------------------------------------------------------------
Combining --
(-5.01)*m + (+X)*w = 0
X = (5.01 * m)/w; since m > w => m/w > 1 ; therefore X will be greater than 5
Thus women's average = 80 + (>5) i.e greater than 85

I like this approach. I used a similar approach using weighted averages.

The general formula is

[(average #1)(a) + (average #2)(b)] = weighted average, where:
a + b = 1, and

a and b represent the relative weightings of the two sub-groups

A similar approach is elaborated in this link
http://www.manhattangmat.com/blog/index ... -problems/
Director
Joined: 25 Apr 2012
Posts: 728
Location: India
GPA: 3.21
Followers: 43

Kudos [?]: 670 [0], given: 723

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

02 Dec 2013, 22:18
rajman41 wrote:
At a certain company, a test was given to a group of men and women seeking for promotions. If the average (artihmetic mean) score for the group was 80, was the average score for the women more than 85?

(1) The average score for the men was less than 75.
(2) The group consisted of more men than women.

Would someone please help me out with this question. I got no clue combining st.1 and 2 and the output of it.

Let A1 = Average score of men
n1= no. of men
A2= Average score of Women
n2= no.of women

Let A be the average of the group which is given as 80 in Q. stem
let n be the total no. of men and women. Clearly, n= n1+n2

Now we know that

n1*A1+n2*A2= n*A ---------------------- > 1

We need to find whether A2 > 85 or not

the above statement can be re-written as

A2= (n*A- n1*A1)/n2

or A2= (n1*A+n2*A- n1*A1)/n2

A2= (n1/n2)*80 + 80 - (n1/n2)*A1

Let n1/n2= x

So A2= 80+ (80-A1)*x -------------------------> 2

Now from st1 we have that A1<75.....

take any value of A1, lets take 74 then the equation 2 becomes

A2= 80 + 6*x --------> Now A2 will depend upon the ration of n1/n2 if n1/n2>/=1 then A2 >85 or else less than 85

St 1 is not sufficient as we don't know the value of x

From st 2 we know that n1/n2> 1 but we don't the value of A 1

hence not sufficient.

Combining both the equation we get that n1/n2>1 and A1 <75 and clearly for any value it will be sufficient.

Ans C.
_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

Intern
Joined: 02 Jul 2014
Posts: 12
Concentration: Marketing, Strategy
Followers: 0

Kudos [?]: 7 [3] , given: 34

At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

20 Jul 2014, 20:32
3
KUDOS
m = average score for the men
w = average score for the women

Statement 1: m<75

if the number of men = the number of women
80-m=w-80
since m<75
80-m=w-80>5
w>85

if the number of men < the number of women
say 1 men and 2 women
80-m=2(w-80)
since m<75
80-m=2(w-80)>5
w>82.5

if the number of men > the number of women
say 2 men and 1 women
2(80-m)=w-80
since m<75
2(80-m)=w-80>10
w>90
Manager
Joined: 11 Sep 2013
Posts: 153
Concentration: Finance, Finance
Followers: 2

Kudos [?]: 90 [0], given: 156

At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

15 Mar 2015, 09:44
3
This post was
BOOKMARKED
To me taking example is easy.
Let total men and women = 6
80 80 80 80 80 80

Statement-1. Let 2 men each got 74. So 12 less from the total. To cover that 12, 4 women have to get 12 more in total. So each is 3 more than 80. It means avg of women is 83. But if no of men is equal to or more than no. of women then avg will be more than 85. So not sure- NS

Statement -2. NS

By combining 2nd example works. Sufficient. Ans C
Intern
Joined: 18 Apr 2015
Posts: 37
Followers: 0

Kudos [?]: 2 [0], given: 5

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

23 Apr 2015, 11:07
Hi Bunnel,

When you say the average of men is 75 , the average of women is X and the average of the group as 80 can X be less that 85.

Are we trying to combine the averages of the two groups i.e (75+X)/2=80 ?

If so doesn't this take the form of weighted average?
Math Forum Moderator
Joined: 06 Jul 2014
Posts: 1274
Location: Ukraine
Concentration: Entrepreneurship, Technology
GMAT 1: 660 Q48 V33
GMAT 2: 740 Q50 V40
Followers: 145

Kudos [?]: 1726 [1] , given: 178

At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

23 Apr 2015, 12:32
1
KUDOS
2
This post was
BOOKMARKED
kirtivardhan wrote:
Hi Bunnel,

When you say the average of men is 75 , the average of women is X and the average of the group as 80 can X be less that 85.

Are we trying to combine the averages of the two groups i.e (75+X)/2=80 ?

If so doesn't this take the form of weighted average?

Hello kirtivardhan

Yes, this is weighted average task. And in case than we have equal quantity of men and women (for example 2) when we have formula that you wrote:

$$\frac{(75m+Xw)}{2}=80$$ and X equal to 85.
And we have more men than women (for example 2 men and 1 woman) and from this information we know that X should be more than 85, because if X equal to 85 we will have

$$\frac{(75*2+85*1)}{3}=78$$ but this is wrong we should have average 80

so X will be equal to 90:

$$\frac{(75*2+90*1)}{3}=80$$
_________________
Manager
Joined: 27 Jan 2015
Posts: 132
Concentration: General Management, Entrepreneurship
GMAT 1: 670 Q44 V38
Followers: 0

Kudos [?]: 22 [0], given: 51

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

23 Apr 2015, 19:51
rajman41 wrote:
At a certain company, a test was given to a group of men and women seeking for promotions. If the average (artihmetic mean) score for the group was 80, was the average score for the women more than 85?

(1) The average score for the men was less than 75.
(2) The group consisted of more men than women.

Would someone please help me out with this question. I got no clue combining st.1 and 2 and the output of it.

1) worthless without knowing the number of people, but lets us know that all men scored under 75 which can be applied to the next statement

2) If the group consisted of more men than women it is fair to assume that in order for LESS woman to pull the average to 80 from 75 they will need to have scored relatively high. We can test this just in case they didn't need to score above 85 though. Set the number of people at 10 and say there are 6 men and 4 women. We can make the following equation

(6*less than 75 + 4x)/10 = 80 ---->(choose the highest number below 75---> ( 74*6 + 4x)/10 = 80

444+4x = 800

4x = 800- 444

4x = 89 <---- This is the *lowest* the females needed to score in order to pull the average up to 80

Intern
Joined: 16 Feb 2015
Posts: 4
Followers: 0

Kudos [?]: 0 [0], given: 9

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

26 Jun 2015, 16:51
I didn't like the long and complicated answer in the book, I like to use logic on this one. I think Bunel explained it really well and it's similar to my thought process as well when looking at the question.

1) This really doesn't give you much information. You know men have an average score of less than 75, but that doesn't really give you any context. Were there more compared to the women? Less compared to the women? Were they equal? Because of that I do not have enough information to accurately say this is sufficient. Therefore (1) is INSUFFICIENT

2) This doesn't give you any information either. So what if there are more men than women? I have no numbers aside from the fact that I know the average is 80. This statement on its own is INSUFFICIENT

Together:
You know that the men make up the majority of the test takers. You also know that they have a total average of less than 75. This MUST mean that the smaller portion of women need to pull the average with the man in it higher, to bring the group average up to 80. The only way this can happen is if the women's average is greater than 80- and in case greater than 85.

Therefore I chose C.
Intern
Joined: 05 Apr 2015
Posts: 10
Followers: 0

Kudos [?]: 2 [0], given: 3

Re: At a certain company, a test was given to a group of men and [#permalink]

### Show Tags

30 Sep 2015, 22:40
A1n1+A2n2=80(n1+n2)
question is asking us is A2>85?
so simply the original question stem for A2
A2=(80-A1)*(n1/n2)+ 80
so.. if A2 has to be greater than 85.. 1st term has to be greater than 5
if A1<75 , n1/n2 is unknown,
if N1/n2 is know still we dont know value of 1st term
comibing the two we know that 1st term has be greater than 6 (suppose we take extreme case for lowest value of 80-74=6)
so A2 will be some value greater than 6 + 80 which is >85
Re: At a certain company, a test was given to a group of men and   [#permalink] 30 Sep 2015, 22:40

Go to page    1   2    Next  [ 23 posts ]

Similar topics Replies Last post
Similar
Topics:
Are 40% of the employees attending the annual company picnic men? 2 05 Aug 2015, 00:07
7 In a certain company, 25% of the women and 17% of the men participate 7 09 Apr 2015, 06:15
19 How long will it take 9 men and 6 women to complete a given task? 7 31 Aug 2014, 03:18
35 A group of men and women gathered to compete in a marathon. 19 17 Nov 2011, 15:42
2 Company Y employs c women and d men. Do the women at Company 4 30 Jun 2011, 18:10
Display posts from previous: Sort by

# At a certain company, a test was given to a group of men and

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.