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At a certain diner, a hamburger (H) and coleslaw (C) cost

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Manager
Manager
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Joined: 09 Jun 2003
Posts: 188
Location: work chair
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At a certain diner, a hamburger (H) and coleslaw (C) cost [#permalink] New post 24 Aug 2003, 04:19
At a certain diner, a hamburger (H) and coleslaw (C) cost $3.59, and a hamburger and french fries (F) cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90

here is my way.

H+C=3.59
H+F=4.40
F=2C

then i have two equation:
H+C=3.59
H+2C=4.40

which is solved like:
H=3.59-C
3.59-C+2C=4.40
C=0.81

but multiplying 0.81 by 2 gives us 1.62, which is not stated among choices. this time, am i wrong or our chinese friends from down3.net are? :?
Manager
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Location: barcelona
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 [#permalink] New post 24 Aug 2003, 06:37
id say you are right
Manager
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Joined: 10 Jun 2003
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 [#permalink] New post 25 Aug 2003, 07:43
You are exactly right. F = 1.62
_________________

Sept 3rd

  [#permalink] 25 Aug 2003, 07:43
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At a certain diner, a hamburger (H) and coleslaw (C) cost

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