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At a certain hospital, 75% of the interns receive fewer than

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Joined: 27 Dec 2012
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Concentration: General Management, Technology
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Kudos [?]: 305 [0], given: 170

Re: At a certain hospital, 75% of the interns receive fewer than [#permalink] New post 28 Jul 2014, 01:37
shivdeepmodi wrote:
Bunuel wrote:
gmatpapa wrote:
At a certain hospital, 75% of the interns receive fewer than 6 hours of sleep and report feeling tired during their shifts. At the same time, 70% of the interns who receive 6 or more hours of sleep report no feelings of tiredness. If 80% of the interns receive fewer than 6 hours of sleep, what percent of the interns report no feelings of tiredness during their shifts?

A. 6
B. 14
C. 19
D. 20
E. 81
Given:



< 6 hours sleep>= 6 hours sleepTOTAL
Tired75--
Not Tired-0.7*X?
TOTAL80X100


Interns who receive < than 6 hours sleep and Not Tired = 80 - 75 = 5;


TOTAL interns who receive >= 6 hours sleep = 100 - 80 = 20, so interns who receive >= 6 hours sleep and are Not Tired = 0.7 * 20 =14;

Interns who are Not Tired = 5 + 14 = 19.

Answer: C.


Guys,
As per the solution : interns with LT6 hours of sleep and tired = 75% of total interns(75 assuming a smart number)
However I calculated it as : 0.75x0.80N. i.e. 75% of 80% of internswith LT6 hours of sleep.(which is obviously wrong).
I am not going very far with such mistakes. :(
Next comes a sillier question: how to avoid such mistakes. :( :???
Regards,
shivdeep


Needless to say, Bunuel's method is perfect :)

There is no need to calculate 75% of 80%

As the answer is expected in percentage, better take the Total interns = 100 so that the %age factor gets computed along
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Re: At a certain hospital, 75% of the interns receive fewer than   [#permalink] 28 Jul 2014, 01:37
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