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At a certain instant in time, the number of cars, N

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At a certain instant in time, the number of cars, N [#permalink]

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At a certain instant in time, the number of cars, N, traveling on a portion of a certain highway can be estimated by the formula

\(N=\frac{20Ld}{600+s^2}\)

where L is the number of lanes in the same direction, d is the length of the portion of the highway, in feet, and s is the average speed of the cars, in miles per hour. Based on the formula, what is the estimated number of cars traveling on a 1/2-mile portion of the highway if the highway has 2 lanes in the same direction and the average speed of the cars is 40 miles per hour? (5,280 feet = 1 mile)

(A) 155
(B) 96
(C) 80
(D) 48
(E) 2
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New post 02 Dec 2012, 08:02
Walkabout wrote:
At a certain instant in time, the number of cars, N, traveling on a portion of a certain highway can be estimated by the formula

\(N=\frac{20Ld}{600+s^2}\)

where L is the number of lanes in the same direction, d is the length of the portion of the highway, in feet, and s is the average speed of the cars, in miles per hour. Based on the formula, what is the estimated number of cars traveling on a 1/2-mile portion of the highway if the highway has 2 lanes in the same direction and the average speed of the cars is 40 miles per hour? (5,280 feet = 1 mile)

(A) 155
(B) 96
(C) 80
(D) 48
(E) 2


Given:
L = 2 lanes;
d = 1/2*5,280 feet;
s = 40 miles per hour.

Thus, \(N=\frac{20*2*\frac{1}{2}*5,280}{600+40^2}=48\).

Answer: D.
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Re: At a certain instant in time, the number of cars, N [#permalink]

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New post 19 Dec 2012, 06:29
\(N=\frac{20*2*(1}{2)*5280/600+40^{2}}\)
\(N=\frac{20 * 5280}{2200}=\frac{528}{11}=48\)

Answer: 48
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How come you wouldn't adjust the speed to 1/2 of 40?
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New post 25 Jun 2013, 02:41
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New post 12 Oct 2013, 09:42
Bunuel wrote:
Walkabout wrote:
At a certain instant in time, the number of cars, N, traveling on a portion of a certain highway can be estimated by the formula

\(N=\frac{20Ld}{600+s^2}\)

where L is the number of lanes in the same direction, d is the length of the portion of the highway, in feet, and s is the average speed of the cars, in miles per hour. Based on the formula, what is the estimated number of cars traveling on a 1/2-mile portion of the highway if the highway has 2 lanes in the same direction and the average speed of the cars is 40 miles per hour? (5,280 feet = 1 mile)

(A) 155
(B) 96
(C) 80
(D) 48
(E) 2


Given:
L = 2 lanes;
d = 1/2*5,280 feet;
s = 40 miles per hour.

Thus, \(N=\frac{20*2*\frac{1}{2}*5,280}{600+40^2}=48\).

Answer: D.



Hi

Is there any shortcut to the calculation?
It took me about 40 seconds to calculate and that's precious time wasted....
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At a certain instant in time, the number of cars, N [#permalink]

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New post 28 Aug 2014, 16:19
ronr34 wrote:

Hi

Is there any shortcut to the calculation?
It took me about 40 seconds to calculate and that's precious time wasted....


(20*(5280/2)*2)/(600+1600)

eliminate 2 = 20*5280/2200
eliminate 2 zero = 2*528/22 = approximately 2*500/20 = 1000/20 = 50 ---> D is closet

Last edited by MulanQ on 12 Sep 2014, 13:51, edited 1 time in total.
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Re: At a certain instant in time, the number of cars, N [#permalink]

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New post 11 Sep 2014, 03:12
Walkabout wrote:
At a certain instant in time, the number of cars, N, traveling on a portion of a certain highway can be estimated by the formula

\(N=\frac{20Ld}{600+s^2}\)

where L is the number of lanes in the same direction, d is the length of the portion of the highway, in feet, and s is the average speed of the cars, in miles per hour. Based on the formula, what is the estimated number of cars traveling on a 1/2-mile portion of the highway if the highway has 2 lanes in the same direction and the average speed of the cars is 40 miles per hour? (5,280 feet = 1 mile)

(A) 155
(B) 96
(C) 80
(D) 48
(E) 2



its very simple & straight stuff but took lot for time for me to understand it. :cry:

(40*5280) / 2 (600+40^2) = 48
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New post 24 Nov 2014, 11:19
At a certain instant in time, the number of cars, N, traveling on a portion of a certain highway can be estimated by the formula

N=\frac{20Ld}{600+s^2}

where L is the number of lanes in the same direction, d is the length of the portion of the highway, in feet, and s is the average speed of the cars, in miles per hour. Based on the formula, what is the estimated number of cars traveling on a 1/2-mile portion of the highway if the highway has 2 lanes in the same direction and the average speed of the cars is 40 miles per hour? (5,280 feet = 1 mile)

(A) 155
(B) 96
(C) 80
(D) 48
(E) 24


I just ballparked to save time= (20*2*2650)=(600+1600), so (20*2*2650)/(2200), just divided by roughly 2200 to leave something like 20*2 left (but a little more). The only answer option close to 40 is 48. So answer D
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New post 01 Aug 2015, 13:34
What I don't understand about this problem is the following

If speed is in miles/hour and distance is in feet . Then why can't we convert feet into miles or vice versa and then perform the calculation ?
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Re: At a certain instant in time, the number of cars, N [#permalink]

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New post 01 Aug 2015, 13:50
Atul11 wrote:
What I don't understand about this problem is the following

If speed is in miles/hour and distance is in feet . Then why can't we convert feet into miles or vice versa and then perform the calculation ?


You need to be economical with your choices in terms of both effort and time spent. Ideally, your best bet is to find a way that gives you the best ROI with least amount of time or energy spent.

Try to change minimum number of variables that will give you the correct answer. There is no 1 way for this question. You can approach it from either direction.

I did it by converting distance from miles to feet (thats it!). It was simple to do this conversion as d was 0.5, much simpler than having a d of 0.23 or 0.37 etc.
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New post 02 May 2016, 15:52
This is an easy one to miss if you don't keep your math straight and don't read the instructions correctly

Let's give it a go

N = (20Ld) / (600+s^2)

L = 2
d = .5(5280) = 2640
s = 40
Plug and Play

N = 20(2)(2640)
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New post 02 May 2016, 15:54
This is an easy one to miss if you don't keep your math straight and don't read the instructions correctly

Let's give it a go

N = (20Ld) / (600+s^2)

L = 2
d = .5(5280) = 2640
s = 40
Plug and Play

N = 20(2)(2640)
....... 600+1600

N = 20(2)(2640)
..........2200

N = 2(2)(264) / 22
N = 2(2)(12)
N = 48
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Walkabout wrote:
At a certain instant in time, the number of cars, N, traveling on a portion of a certain highway can be estimated by the formula

\(N=\frac{20Ld}{600+s^2}\)

where L is the number of lanes in the same direction, d is the length of the portion of the highway, in feet, and s is the average speed of the cars, in miles per hour. Based on the formula, what is the estimated number of cars traveling on a 1/2-mile portion of the highway if the highway has 2 lanes in the same direction and the average speed of the cars is 40 miles per hour? (5,280 feet = 1 mile)

(A) 155
(B) 96
(C) 80
(D) 48
(E) 2


Although this problem may seem wordy and confusing, it has much more bark than bite. In the given equation, we have variables L, d, and S, and the entire equation is set equal to N.

We also are told the following:

N = the number of cars in a certain instant in time

L = number of lanes in the same direction

d = length of the portion of the highway, in feet

s = average speed of the cars, in miles per hour

We are given the following values for the variables:

d = ½ mile

L = 2 lanes

s = 40 mph

Before plugging these values into the equation, we must convert ½ mile to feet. Since we know that (5,280 feet = 1 mile), we know that:

½ mile = ½ x 5,280 = 2,640 feet

So now we can plug all this info into the equation to determine the estimated number of cars N.

N = (20Ld)/(600 + s^2)

N = (20 x 2 x 2,640)/(600 + 40^2)

N = (40 x 2,640)/2,200

N = (4 x 264)/22

N = (2 x 264)/11

N = 528/11 = 48

Answer D.

Note: Notice that at the end we kept reducing our equation so that we did not have to work with numbers that were too large; keep things as simple as possible.
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New post 17 May 2016, 19:08
Attached is a visual that should help.
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Screen Shot 2016-05-17 at 7.06.46 PM.png
Screen Shot 2016-05-17 at 7.06.46 PM.png [ 114.46 KiB | Viewed 1269 times ]

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Re: At a certain instant in time, the number of cars, N [#permalink]

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New post 13 Jul 2016, 14:25
What i do not understand is: on the highways, cars go in two different directions, that is a common knowledge, so having to estimate number of cars on the highway, not on the part of the highway that goes only in one direction, implies that number of lanes has to be multiplied by 2.
I think this is a clear miss in the problem wording, there is no leap of additional knowledge required, it is pretty much as taking for granted that sun rises on the east, yet for some reason problem gives it that highway has only one direction, which completely inconsistent with reality.
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New post 13 Jul 2016, 16:42
v1801philip wrote:
What i do not understand is: on the highways, cars go in two different directions, that is a common knowledge, so having to estimate number of cars on the highway, not on the part of the highway that goes only in one direction, implies that number of lanes has to be multiplied by 2.
I think this is a clear miss in the problem wording, there is no leap of additional knowledge required, it is pretty much as taking for granted that sun rises on the east, yet for some reason problem gives it that highway has only one direction, which completely inconsistent with reality.


If you read carefully, it says in the question that L represents the number of lanes going in the same direction. You don't need to multiply the answer by 2, because the formula is for the number of cars traveling on a portion of a certain highway, which is exactly what you are solving for and thus the formula provided should have already accounted for that fact.

If for some reason the formula provided by GMAC were flawed or open-ended, then you still wouldn't be responsible for realizing that fact, so I suggest that you just trust the formula as it is.

"At a certain instant in time, the number of cars, N, traveling on a portion of a certain highway can be estimated by the formula (...) where L is the number of lanes in the same direction, d is the length of the portion of the highway, in feet, and s is the average speed of the cars, in miles per hour. Based on the formula, what is the estimated number of cars traveling on a 1/2-mile portion of the highway if the highway has 2 lanes in the same direction and the average speed of the cars is 40 miles per hour? (5,280 feet = 1 mile)"
At a certain instant in time, the number of cars, N   [#permalink] 13 Jul 2016, 16:42
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