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# At a certain pet shop, 1/3 of the pets are dogs and 1/5 of

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At a certain pet shop, 1/3 of the pets are dogs and 1/5 of [#permalink]  18 May 2007, 10:11
At a certain pet shop, 1/3 of the pets are dogs and 1/5 of the pets are birds. How many of the pets are dogs?

1)there are 30 birds in the shop
2)there are 20 more birds than dogs in the shop

The answer is E, but I put D because I think to myself....are there other types of animals in the shop? If so, they are unknown....so, I can't solve it. Why am I wrong?
Senior Manager
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first i was a little bit confused...
I thought it's D, but it looked to simple
the trick is the statement in the problem tells us that there are more dogs in the store than birds 1/3>1/5 so statement 2 is not sufficient (it's controversial)
statement 1 is sufficient we can find the total number of pets. 150 and the number of dogs 150/3=50

Am I missing something?
VP
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1/3 dogs = 5/15

1/5 birds = 3/15

statement 1

there are 30 birds in the shop

so 30*15/3 = 150 total animals

150*5/15 = 50 dogs

sufficient

statement 2

there are 20 more birds ??? than dogs ??? in the shop (see sergey post)

x = dogs = 5/15

x+20 = birds = 3/15

5/15-3/15 = 2/15

20*15/2= 150 total animals

150*5/15 = 50 dogs

Last edited by KillerSquirrel on 18 May 2007, 10:57, edited 1 time in total.
VP
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Sergey_is_cool wrote:
first i was a little bit confused...
I thought it's D, but it looked to simple
the trick is the statement in the problem tells us that there are more dogs in the store than birds 1/3>1/5 so statement 2 is not sufficient (it's controversial)
statement 1 is sufficient we can find the total number of pets. 150 and the number of dogs 150/3=50

Am I missing something?

you are correct , the statements are contradicting each other!!!

so unless the problem is presented wrong the answer is (E)

whenever both statements contradict each other i always put (E) !

Intern
Joined: 15 Jan 2007
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KillerSquirrel wrote:
Sergey_is_cool wrote:
first i was a little bit confused...
I thought it's D, but it looked to simple
the trick is the statement in the problem tells us that there are more dogs in the store than birds 1/3>1/5 so statement 2 is not sufficient (it's controversial)
statement 1 is sufficient we can find the total number of pets. 150 and the number of dogs 150/3=50

Am I missing something?

you are correct , the statements are contradicting each other!!!

so unless the problem is presented wrong the answer is (E)

whenever both statements contradict each other i always put (E) !

i could be wrong but dont recall seeing such contradictions in OG11. so not a good question ?
VP
Joined: 08 Jun 2005
Posts: 1146
Followers: 6

Kudos [?]: 136 [0], given: 0

svas - you are right ! , usually question like those comes from dubious sources. and sometimes the question is wrongly written.

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