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At a certain school, the ratio of the number of second

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Director
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At a certain school, the ratio of the number of second [#permalink] New post 24 Apr 2006, 01:21
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A
B
C
D
E

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0% (00:00) correct 0% (00:00) wrong based on 1 sessions
At a certain school, the ratio of the number of second graders to the number of fourth graders is 8 to 5, and the ratio of the number of first graders to the number of second graders is 3 to 4. If the ratio of the number of third graders to the number of fourth graders is 3 to 2, what is the ratio of the number of first graders to the number of third graders?

A. 16 to 15
B. 9 to 5
C. 5 to 16
D. 5 to 4
E. 4 to 5
VP
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 [#permalink] New post 24 Apr 2006, 01:36
4/5

Ans is E...


Normalize all the numerators demonimators! (Use Lowest Common Denomintor).

You should get the value!
Intern
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 [#permalink] New post 24 Apr 2006, 04:17
A=1st grade
B=2nd grade
C=3rd grade
D=4th grade

We have:
B:D
8:5

A:B
3:4

C:D
3:2

We are looking for: A:C ?
1°)
A:D
6:5

2°)
A:C
12:15 = 4:5

Answer: 4:5
Director
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 [#permalink] New post 24 Apr 2006, 04:45
Anybody else? :wink:
Manager
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 [#permalink] New post 24 Apr 2006, 11:24
g1/g3 = (g1/g2) * (g2/g4) * (g4/g3)

= (3/4) *(8/5) * (2/3)

=4/5

so the ratio is 4:5

g1 g2 g3 g4 are the grades
Intern
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 [#permalink] New post 24 Apr 2006, 15:43
Thanks IPC302, your technique is much faster than mine!
GMAT Club Legend
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 [#permalink] New post 24 Apr 2006, 17:54
2nd:4th = 8:5
1st:2nd = 3:4
3rd:4th = 3:2

1st:3rd = ??

We can work out:

1st:2nd:3rd:4th
12:16:15:10

So 1st/3rd = 12/15 = 4/5
Director
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 [#permalink] New post 25 Apr 2006, 10:22
OA is 'E'
Great explanation guys.
  [#permalink] 25 Apr 2006, 10:22
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