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At a certain stage of a soccer tournament, the score ratio

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At a certain stage of a soccer tournament, the score ratio [#permalink] New post 01 Dec 2012, 06:28
At a certain stage of a soccer tournament, the score ratio of teams A, B and C was 3:4:5. Eventually, the score ratio of A to B has doubled while the score ratio of A to C has halved. If the final score of team C was 40, what was the final score of team B?

1)8
2)10
3)20
4)40
5)80

I tried this as below:

a:b:c = 3:4:5

a:b= 3:4

doubled:
a:b = 2* 3:4 = 3:2

halved
a:c = (1/2)*3:5 = 3:10

a:c/a:b = (3/10)/ (3/2) = 6/30

given c =40

substituting, we get b = 8.

Pls let me know the basic approach on this.
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Re: Need help on this Ratio basics [#permalink] New post 01 Dec 2012, 06:44
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manukumar wrote:
At a certain stage of a soccer tournament, the score ratio of teams A, B and C was 3:4:5. Eventually, the score ratio of A to B has doubled while the score ratio of A to C has halved. If the final score of team C was 40, what was the final score of team B?

1)8
2)10
3)20
4)40
5)80

I tried this as below:

a:b:c = 3:4:5

a:b= 3:4

doubled:
a:b = 2* 3:4 = 3:2

halved
a:c = (1/2)*3:5 = 3:10

a:c/a:b = (3/10)/ (3/2) = 6/30

given c =40

substituting, we get b = 8.

Pls let me know the basic approach on this.


A to B = 3 : 4

So, on doubling we get 6 : 4

A to C = 3 : 5

So, on halving we get 1.5 : 5 or 3 : 10 or 6 : 20

So final ratio = 6 : 4 : 20.

If 20x = 40

4x = 8

Hence, answer is A
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Joined: 15 Nov 2012
Posts: 4
Location: United States
Concentration: General Management, Technology
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Kudos [?]: 5 [0], given: 3

Re: Need help on this Ratio basics [#permalink] New post 01 Dec 2012, 06:46
Just as mine :) Thanks ....
Re: Need help on this Ratio basics   [#permalink] 01 Dec 2012, 06:46
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At a certain stage of a soccer tournament, the score ratio

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