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# At a certain university the ratio of the number of teaching

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At a certain university the ratio of the number of teaching [#permalink]

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24 Feb 2008, 15:40
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At a certain university the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:80. At this university, what is the maximum number of students possible in a course that has 5 teaching assistants ?
A. 130
B. 131
C. 132
D. 133
E. 134
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Re: Maths: Number of teaching assistants [#permalink]

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24 Feb 2008, 16:22
suntaurian wrote:
At a certain university the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:80. At this university, what is the maximum number of students possible in a course that has 5 teaching assistants ?
A. 130
B. 131
C. 132
D. 133
E. 134

Tricky. I'll go with (D).

3 : 80 = 5 : 133.3

The closest maximum ratio (among the options provided) greater than 5:133.3 is 5:133. Hence (D)
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Re: Maths: Number of teaching assistants [#permalink]

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24 Feb 2008, 16:29
OA is D.

I had gotten so far also, but then saw that the ratio has to be greater than 3:80 and for calculation purposes I had written it as 80:3..and to get a ratio of X:5 > 80:3, I rounded 133.3 to 134 and marked E.
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Re: Maths: Number of teaching assistants [#permalink]

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24 Feb 2008, 16:44
suntaurian wrote:
OA is D.

I had gotten so far also, but then saw that the ratio has to be greater than 3:80 and for calculation purposes I had written it as 80:3..and to get a ratio of X:5 > 80:3, I rounded 133.3 to 134 and marked E.

To be fair, I almost went for (E) too. Then it just occured that the question can't be that easy! +1
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Re: Maths: Number of teaching assistants [#permalink]

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24 Feb 2008, 23:58
suntaurian wrote:
At a certain university the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:80. At this university, what is the maximum number of students possible in a course that has 5 teaching assistants ?
A. 130B. 131C. 132D. 133E. 134

5/x > 3/80
for 3 its 80
for 1 its 80/3
for 5 its (80x5/3)
so x = 400/3 or 133.3
to have 5/x > 3/80, x should be smaller. so it is 133 rather than 134..
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Re: Maths: Number of teaching assistants [#permalink]

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26 Feb 2008, 08:36
suntaurian wrote:
At a certain university the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:80. At this university, what is the maximum number of students possible in a course that has 5 teaching assistants ?
A. 130
B. 131
C. 132
D. 133
E. 134

5/x>3/80 --> 133.33>x.

E cannot be it. Since X can be less than 133.3333... and were not given any other constraints the closest integer is 133. Thus D
Re: Maths: Number of teaching assistants   [#permalink] 26 Feb 2008, 08:36
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