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At a dinner party

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Manager
Manager
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Joined: 12 Nov 2011
Posts: 55
GMAT Date: 12-15-2011
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Kudos [?]: 0 [0], given: 1

At a dinner party [#permalink] New post 06 Dec 2011, 20:11
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

11% (00:00) correct 89% (00:27) wrong based on 18 sessions
At a dinner party, 5 people are to be seated around a circular table. two seating arrangement are considered different only when the position of the people are different relative to each other. what is the total number of possible seating arrangement for the group?
a.5
b.10
c.24
d.32
e.120
[Reveal] Spoiler: OA
Manager
Manager
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Joined: 26 Apr 2011
Posts: 226
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Kudos [?]: 31 [0], given: 12

GMAT ToolKit User GMAT Tests User
Re: At a dinner party [#permalink] New post 06 Dec 2011, 22:38
for 5 people seating arrangement around a circular table = (5-1)!
= 4!
= 4*3*2*1
=24

OA is C
Manager
Manager
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Joined: 12 Nov 2011
Posts: 55
GMAT Date: 12-15-2011
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Re: At a dinner party [#permalink] New post 06 Dec 2011, 22:44
Anyone can explain carefully???
Manager
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Kudos [?]: 31 [0], given: 12

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Re: At a dinner party [#permalink] New post 06 Dec 2011, 23:22
Hi for n things to make circular arrangement there are (n-1)! ways.
Based on this concept you can solve this question.

How this formula came: say you have n things which you want to arrange circularly.

fix 1 thing first. Now there can be (n-1)! different arrangement of rest things around first.

so total ways of arranging n thins circularly (n-1)!
hope this will help you.
Intern
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Joined: 01 Dec 2011
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Re: At a dinner party [#permalink] New post 20 Dec 2011, 12:30
Is the OA A or C? I assume OP is wrong and the answer is C.
Senior Manager
Senior Manager
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Status: D-Day is on February 10th. and I am not stressed
Affiliations: American Management association, American Association of financial accountants
Joined: 12 Apr 2011
Posts: 275
Location: Kuwait
Schools: Columbia university
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Kudos [?]: 45 [0], given: 52

GMAT Tests User
Re: At a dinner party [#permalink] New post 21 Dec 2011, 12:46
for seating arrangement around a circular table, the permutation formula is

(n-1)!====> (5-1)!=4!=24
_________________

Sky is the limit

Re: At a dinner party   [#permalink] 21 Dec 2011, 12:46
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At a dinner party

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