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At a fruit stand yesterday, the price of each apple was $0.1

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gorden
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At a fruit stand yesterday, the price of each apple was $0.1 [#permalink] New post   Updated on: 27 May 2013, 05:27
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At a fruit stand yesterday, the price of each apple was $0.10 more than the price of each orange. What was the total revenue from the sale of oranges at the fruit stand yesterday?

(1) The number of oranges sold at the fruit stand yesterday was 5 more than the number of apples.
(2) The total revenue from the sale of apples at the fruit stand yesterday was $15.00
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E

Originally posted by gorden on 19 Nov 2008, 20:04.
Last edited by Bunuel on 27 May 2013, 05:27, edited 3 times in total.
Edited the question and added the OA
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Re: apple and orange---25 [#permalink] New post   20 Nov 2008, 06:26
gorden wrote:
At a fruit stand yesterday, the price of each apple was $0.10 more than the price of each orange. What was the total revenue from the sale of oranges at the fruit stand yesterday?
(1) The number of oranges sold at the fruit stand
yesterday was 5 more than the number of
apples.
(2) The total revenue from the sale of apples
at the fruit stand yesterday was $15.00


Let the cost of each orange be x
therefore, the cost of apple = x+ 0.1

Let the number of Apple be A, and number of Orange be Q
So..
2) A(x+0.1) = 15 .. we don't know the number of orange sold. insufficient
1) Q = A + 5
We don't know the cost as well as the value of Q & A, insufficient
Combining A & B
We have to find the value of Qx + A(x+0.1)
2 equation, 3 variables..
Question cannot be solved.
E is the answer.;
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rohitgoel15
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Re: apple and orange---25 [#permalink] New post   19 Mar 2012, 00:04
lgon wrote:
gorden wrote:
At a fruit stand yesterday, the price of each apple was $0.10 more than the price of each orange. What was the total revenue from the sale of oranges at the fruit stand yesterday?
(1) The number of oranges sold at the fruit stand
yesterday was 5 more than the number of
apples.
(2) The total revenue from the sale of apples
at the fruit stand yesterday was $15.00


Let the cost of each orange be x
therefore, the cost of apple = x+ 0.1

Let the number of Apple be A, and number of Orange be Q
So..
2) A(x+0.1) = 15 .. we don't know the number of orange sold. insufficient
1) Q = A + 5
We don't know the cost as well as the value of Q & A, insufficient
Combining A & B
We have to find the value of Qx + A(x+0.1)
2 equation, 3 variables..
Question cannot be solved.
E is the answer.;


Hi,

Can anyone confirm the OA and the method? As per my source the OA should be C , though i am myself getting E as the ans.

Cheers
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Re: apple and orange---25 [#permalink] New post   19 Mar 2012, 07:27
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rohitgoel15 wrote:
At a fruit stand yesterday, the price of each apple was $0.10 more than the price of each orange. What was the total revenue from the sale of oranges at the fruit stand yesterday?
(1) The number of oranges sold at the fruit stand yesterday was 5 more than the number of apples.
(2) The total revenue from the sale of apples at the fruit stand yesterday was $15.00

Hi,

Can anyone confirm the OA and the method? As per my source the OA should be C , though i am myself getting E as the ans.

Cheers


Your answer is correct and the OA from the source is wrong.

Consider following two cases for (1)+(2):
A. Oranges are free and apples are for $0.1, so the revenue of $15 (150 apples) from the sale of apples would be the total revenue, which makes the revenue from the sale of oranges zero;
B. Oranges are for $0.5 and apples are for $0.15, for this case clearly there will be some revenue from the sale of oranges.

Answer: E.
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Re: At a fruit stand yesterday, the price of each apple was $0.1 [#permalink] New post   17 Jan 2024, 06:18
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Re: At a fruit stand yesterday, the price of each apple was $0.1 [#permalink]
17 Jan 2024, 06:18
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