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At a garage sale, all of the prices of the items sold were

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At a garage sale, all of the prices of the items sold were [#permalink] New post 28 Jan 2012, 03:06
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At a garage sale, all of the prices of the items sold were different. If the price of a radio sold at the garage sale was both the 15th highest price and the 20th lowest price among the prices of the items sold, how many items were sold at the garage sale?

A. 33
B. 34
C. 35
D. 36
E. 37
[Reveal] Spoiler: OA

Last edited by Bunuel on 28 Jan 2012, 03:26, edited 1 time in total.
Added the OA
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Re: At a garage sale, all of the prices of the items sold were [#permalink] New post 28 Jan 2012, 04:23
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RadhaKrishnan wrote:
Why do we add -1 ?


In 15+20 the item is counted TWICE: in 15 (as it's 15th highest priced item) as well as in 20 (as it's 20th lowest priced item), hence we should subtract 1 to get rid of double counting.
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Re: Numbers [#permalink] New post 28 Jan 2012, 03:25
Expert's post
RadhaKrishnan wrote:
At a garage sale, all of the prices of the items sold were different. If the price of a radio sold at the garage sale was both the 15th highest price and the 20th lowest price among the prices of the items sold, how many items were sold at the garage sale?

A. 33
B. 34
C. 35
D. 36
E. 37


As the price of an item was BOTH 15th highest price and the 20th lowest price then # of items is: 15+20-1=34.

Answer: B.
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Re: At a garage sale, all of the prices of the items sold were [#permalink] New post 05 Oct 2013, 06:40
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Re: At a garage sale, all of the prices of the items sold were   [#permalink] 05 Oct 2013, 06:40
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