Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

At a loading dock, each worker on the night crew loaded [#permalink]

Show Tags

07 Oct 2010, 08:12

3

This post received KUDOS

22

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

70% (02:56) correct
30% (02:01) wrong based on 1035 sessions

HideShow timer Statistics

At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?

At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? (A) 1/2 (B) 2/5 (C) 3/5 (D) 4/5 (E) 5/8

Pick some smart numbers. Let the day crew has 5 workers and each day crew worker loads 4 boxes, so total boxes loaded by the day crew is 5*4=20;

Then the night crew would have 5*4/5=4 workers and each night crew worker would load 4*3/4=3 boxes, so total boxes loaded by the night crew would be 4*3=12;

Re: Help me with the ANSWER .. Rates + Ratio Question. [#permalink]

Show Tags

07 Oct 2010, 10:05

2

This post received KUDOS

Just take the Box Loaded by each Night crew is Bn and Box Loaded by each Day Crew is Bd.Then According to question (Bn)=(3/4)(Bd) i.e (Bn)/(Bd)=3/4

Now again let Night Crew Has Nn number of crew members and Day crew has Nd members.Then according to question (Nn)=(4/5)(Nd) i.e (Nn)/(Nd)=4/5

As number of box carried by the group will be the product of Number of crew multiplied by the number of boxes carried by each member, According to question we need to find out { (Nd)(Bd) } / { (Nn)(Bn)+(Nd)(Bd) }

Dividing the Nominator and denominator by (Nd)(Bd),

Re: Help me with the ANSWER .. Rates + Ratio Question. [#permalink]

Show Tags

07 Oct 2010, 23:13

its 5/8, Work done by day crew will be 4x (let x=1), the count of day crew = 5x Work done by day crew will be 3x (let x=1), the count of day crew = 4x Total amount work done by both is 5*4+4*3 = 20+12 = 32 Ratio of amount of work done by day crew to total amount of work done is = 20/32 =5/8.

At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all boxes loaded by two crews did the day crew load? A 1/2 B 2/5 C 3/5 D 4/5 E 5/8

night crew loads 3/4 of what day crew loads.

Also, night crew is 4/5th day crew.

Therefore if one day crew member loads x boxes Night crew is 4/5th of (1 ) * 3/4 = 3/5x

Therefore total number of boxes per crew member (1 night + one day crew) 3/5x +x = 8/5x.

Re: Please help me understand this question in terms of solving [#permalink]

Show Tags

26 Mar 2011, 05:40

2

This post received KUDOS

scbguy wrote:

at a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load ?

A) 1/2 B)2/5 C)3/5 D)4/5 E)5/8

Please explain the step by step working of this question. Thanks

Say, Day crew = 5 people Night crew = (4/5)*5 = 4 people

Each person in day crew loaded = 4 boxes. Each person in night crew loaded = (3/4)*4= 3 boxes.

Total boxes loaded by day crew = 5*4 = 20 Total boxes loaded by night crew = 4*3 = 12

Fraction of boxes loaded by day crew = 20/(20+12) = 20/32 = 5/8

at a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load ?

A) 1/2 B)2/5 C)3/5 D)4/5 E)5/8

Please explain the step by step working of this question. Thanks

Workers at night crew loaded 3/4 as many boxes as did day crew so they loaded fewer boxes. Night crew has 4/5 as many workers as the day crew so night crew has fewer workers too. Overall, night crew loaded 3/4 * 4/5 = 3/5 as many boxes as did day crew. So out of a total of 8 boxes, Night Crew loaded 3 and Day Crew loaded 5 so Day Crew loaded 5/8 of total boxes. Or Boxes loaded by Night Crew: Boxes loaded by Day Crew = 3/5 : 1 = 3:5 So day crew loaded 5/8 of total boxes.

Re: OG12 PS 138- Loading dock and workers [#permalink]

Show Tags

22 Sep 2011, 13:59

Hi, I'm trying to plug in for Question # 138 in OG 12. Could anyone point out where i'm going wrong in my reasoning? I understand the solutions posted in the earlier posts but would like to know where i went wrong. No. of Boxes loaded by Night workers = 3/4 of Day workers No. of Night workers = 4/5 of Day workers.

Let the number of Day workers = 100 and they load a total of 100 boxes. No. of boxes loaded by Night workers = 3/4 x 100 = 75 No. of Night workers = 4/5 x 100 = 80

total no. of boxes loaded by both workers = 175 total no. of boxes loaded by day workers = 100

fraction of boxes loaded by day workers out of the total = 100/175 = 4/7 The closest answer is 4/5 which is D.

Hi, I'm trying to plug in for Question # 138 in OG 12. Could anyone point out where i'm going wrong in my reasoning? I understand the solutions posted in the earlier posts but would like to know where i went wrong. No. of Boxes loaded by Night workers = 3/4 of Day workers No. of Night workers = 4/5 of Day workers.

Let the number of Day workers = 100 and they load a total of 100 boxes. No. of boxes loaded by Night workers = 3/4 x 100 = 75 No. of Night workers = 4/5 x 100 = 80

total no. of boxes loaded by both workers = 175 total no. of boxes loaded by day workers = 100

fraction of boxes loaded by day workers out of the total = 100/175 = 4/7 The closest answer is 4/5 which is D.

But the correct answer is 5/8 which is E.

Here is the problem in your solution: It is given that EACH night worker loads 3/4 of the boxes loaded by EACH day worker. (not that total number of boxes loaded by night workers is 3/4 of the boxes loaded by day workers)

If I want to take values and I say, each day worker loads 100 boxes, then each night worker loads 75 boxes. Total no of boxes loaded by day workers = 100*100 = 10,000 Total no of boxes loaded by night workers = 80*75 = 6000

Fraction of total boxes loaded by day workers = 10,000/16,000 = 5/8

Though, if I want to take numbers and plug in, I would take easier numbers. Say, there are 5 day workers. Then there are 4 night workers. Say, each day worker loads 4 boxes in a day. Each night worker then loads 3 boxes in a day. Total no of boxes loaded by day workers = 5*4 = 20 Total no of boxes loaded by night workers = 4*3 = 12 Fraction of boxes loaded by day workers = 20/32 = 5/8 _________________

Re: OG12 PS 138- Loading dock and workers [#permalink]

Show Tags

01 Mar 2012, 04:30

1

This post received KUDOS

2

This post was BOOKMARKED

I think that the biggest problem for solving this kind of questions is the language understanding (i.e. misunderstanding). I've had a lot of trouble with this one until I figured out that the night crew did 3/4 and the day crew did 4/4 of the work. And that the night crew had 4/5 workers and the day crew 5/5 workers. It can become quite messy for a non-native person. _________________

#138 in OG 12 edition problem solving word problem [#permalink]

Show Tags

12 Apr 2012, 19:21

If you don't have the book in front of you the question is:

At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? a. 1/2 b. 2/5 c. 3/5 d. 4/5 e. 5/8

I didn't know how to answer this question so I looked at the answer explanations and I still do not understand how to get the answer. The explanation says:

From this, the workers on the night crew will load 3/4(4/5)= 3/5 as many boxes as the day crew. The total loaded by both the day and night crews is thus 1 + 3/4= 5/5 + 3/5= 8/5 of the day crew's work. Therefore, the fraction of all the boxes loaded by the two crews that was done by the day crew was 1/8/5 = 1(5/8) = 5/8.

I understand the first sentence saying that the night crew will load 3/5 as many boxes as the day crew. Where I get mixed up is in the next sentence, The total loaded by both the day and night crews is thus 1 + 3/5 = 5/5 + 3/5 = 8/5 of the day crew's work. I do not understand where the 1 comes from. I am figuring that the number 1 represents the day crew. Is it saying the night crew loads 3/5 as many as the day crew so the day crew loads 5/5? Can someone please explain this to me??

Re: #138 in OG 12 edition problem solving word problem [#permalink]

Show Tags

12 Apr 2012, 20:03

1

This post received KUDOS

At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? a. 1/2 b. 2/5 c. 3/5 d. 4/5 e. 5/8

SEE IT THIS WAY:

day crew loads=x boxes/ member night crew loads = 3x/4 boxes/ member

day crew workers= y night crew workers= 4y/5

total boxes loaded/ day= xy+ (3x/4)*(4y/5)= xy+3xy/5= 8xy/5

required fraction= xy/(8xy/5) = 5/8

Hence E

Hope this clarifies..!! _________________

Practice Practice and practice...!!

If my reply /analysis is helpful-->please press KUDOS If there's a loophole in my analysis--> suggest measures to make it airtight.

Re: At a loading dock, each worker on the night crew loaded [#permalink]

Show Tags

09 Oct 2013, 06:38

2

This post received KUDOS

I picked some smart numbers and used a table to organize the given information. Just another way to visualize the problem for me... So, let's say we have 5 day workers. That would give us 4 night workers (4/5 of day). Say the day workers load 12 boxes (I picked a smart-ish number), then the night workers would load 9 boxes (3/4 of what the Day workers load). Put it all in a table and see what you have.

--------- Day ---- Night ----- Total People---- 5-------- 4------------ Boxes ---- 12 -------9 ----------- Total -----60-------36--------96

I arrived at the Totals on the bottom by multiplying the people and boxes (5x12, 4x9).

So if you want to figure out what fraction of the total the day workers loaded, use:

\(\frac{60}{96}\)

This is (number of boxes the day crew loaded) divided by (total number of boxes)

This simplifies to \(\frac{5}{8}\). Thus, E is the answer.

Re: At a loading dock, each worker on the night crew loaded [#permalink]

Show Tags

27 Oct 2014, 18:07

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

At a loading dock, each worker on the night crew loaded [#permalink]

Show Tags

07 Jan 2015, 14:36

Let b - boxes and w - workers

Night crew loaded 0.75b per worker with 0.8w workers => 0.6bw Day crew loaded b per worker with w workers => bw Total loaded by both => 1.6bw Finally, divide bw / 1.6bw <=> 1/1.6 = 5/8

At a loading dock, each worker on the night crew loaded [#permalink]

Show Tags

15 Jun 2015, 01:01

Question:

Okay so I got that far that the night crew loads 3/5 as many boxes as the day crew. However I then calculated 3/5 divided by 5/5 (total in my opinion).

I looked at the OG's solution and I don't get why we first add 5/5 to 3/5. It does not make sense in my head as the total number of boxes would then be greater than 100%? Maybe its a language problem as the problem is kind of wordy...

At a loading dock, each worker on the night crew loaded [#permalink]

Show Tags

18 Jun 2015, 01:17

I just calculated the number of boxes (for ONE worker) for the number or workers (based on the information in the stem), and found #boxes*#workers for each shift:

This is the kickoff for my 2016-2017 application season. After a summer of introspect and debate I have decided to relaunch my b-school application journey. Why would anyone want...

Check out this awesome article about Anderson on Poets Quants, http://poetsandquants.com/2015/01/02/uclas-anderson-school-morphs-into-a-friendly-tech-hub/ . Anderson is a great place! Sorry for the lack of updates recently. I...

According to the Nebula Award categories, a novel must be over 40,000 words. In the past year I have written assignments for 22 classes totaling just under 65...