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Intern
Joined: 05 May 2007
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at a loading dock,each worker on the night crew loaded 3/4 as man boxes as each worker on day crew.If the night crew has 4/5 as many workers as day crew,what fraction of all the boxes loaded by the two crews did the day crew load?
a. 1/2
b.2/5
c. 3/5
d. 4/5
e 5/8
Senior Manager
Joined: 28 Feb 2007
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E.
Day workers(DW) :5
eache DW loads N boxes then Total for DW=5*N
Night workers(NW):4
each loads 3N /4 then Total boxes for NW=4*(3N /4)=3N

So 5N/8N=5/8
Senior Manager
Joined: 28 Feb 2007
Posts: 306
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Kudos [?]: 32 [0], given: 0

arian75 wrote:
did you assume Dw= 5
how did assume that?

U don't need to assume anything. I used this method just to make problem easier. LOOK:

Day workers(DW) :5a
eache DW loads N boxes then Total for DW=5a*N
Night workers(NW):4a
each loads 3N /4 then Total boxes for NW=4a*(3N /4)=3aN

So 5aN/8aN=5/8 . See it doesn't affect on solution.
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