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At a monthly meeting, 2/5 of the attendees were males and

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At a monthly meeting, 2/5 of the attendees were males and [#permalink]

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New post 01 Jun 2008, 09:38
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Difficulty:

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Question Stats:

88% (02:32) correct 13% (01:25) wrong based on 111 sessions

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At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?

A. 11/100
B. 3/25
C. 7/50
D. 3/20
E. 4/25
[Reveal] Spoiler: OA
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Director
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Re: PS_meeting [#permalink]

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New post 01 Jun 2008, 09:49
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One can pick number or one can also do it without picking number depending on how comfortable one is with abstract calculations.
For picking a number choose some thing that can be evenly divided by all the denominators given in the question.
Solution by picking number
Picking nunber = 100
Males = 100*2/5 = 40
Female = 100 - 40 = 60
Males Arrived on time = 40 * 7/8 = 35
Males Not Arrived on time = 40 - 35 = 5
Females Arrived on time = 60 * 9/10 = 54
Females Not Arrived on time = 60 - 54 = 6
Total later arrivals = 6 + 5 = 11
Ratio = 11/100

Answer A.

Solution by abstract method
Total nunber = x
Males = x*2/5 = 2x/5
Female = x - 2x/5 = 3x/5
Males Not Arrived on time = 2x/5 * (1-7/8) = x/20
Females Not Arrived on time = 3x/5 * (1-9/10) = 3x/50
Total later arrivals = x/20 + 3x/50 = 11x/100
Ratio = 11x/100/x = 11/100

Answer A.
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Re: PS_meeting [#permalink]

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New post 01 Jun 2008, 09:50
i get 11/100

i picked 100 cause its a multiple of 5, 2..
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Re: PS_meeting [#permalink]

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New post 01 Jun 2008, 11:25
I find that it is easier to draw the table and fill in the blanks, it saves a little time of having to set up the conditions in the mind

| M | F | Total
late | | |
not late | | |
total | 2/5 | 3/5 | 5/5

the table does not show like I intended for it to show
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Re: At a monthly meeting, 2/5 of the attendees were males and [#permalink]

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New post 24 Nov 2012, 08:09
2/5 of the attendees were males and 7/8 of the male attendees

How to pick nos? Here it is..

LCM of 5 and 8 is 40..
So pick no 40 for no of males..

so males=2/5 of total attendees= 40



therefore total=100.

7/8 of 40= 35 arrived on time

Hope it helps :)

Kudos if you like this approach..
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Re: At a monthly meeting, 2/5 of the attendees were males and [#permalink]

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New post 02 Dec 2012, 13:00
Sachin9 wrote:
2/5 of the attendees were males and 7/8 of the male attendees

How to pick nos? Here it is..

LCM of 5 and 8 is 40..
So pick no 40 for no of males..

so males=2/5 of total attendees= 40



therefore total=100.

7/8 of 40= 35 arrived on time

Hope it helps :)

Kudos if you like this approach..



I got the answer right because after I couldn't figure it out picking numbers, I tried to solve another way but I was wondering if you could help me figure it out with picking numbers approach.

How do we know to pick numbers for males and not total attendees? I picked 40 because it went into 5, 8, and 10. Then I figured out 2/5 of males of total attendees is 16 and 7/8 of 16 on time is 14 on time which means 2 not on time.

If 2/5 were males then that means 3/5 were females so 3/5 of the 40 is 24. 9/10 of that number is approximately 21 people which is approximately 3 females not on time.

Then that would be 3 females not on time + 2 males not on time = 5 / 40= 1/8
Re: At a monthly meeting, 2/5 of the attendees were males and   [#permalink] 02 Dec 2012, 13:00
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