At a particular store, candy bars are normally priced at $1.

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At a particular store, candy bars are normally priced at $1. [#permalink]

13 Jan 2013, 03:16

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86% (01:44) wrong

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At a particular store, candy bars are normally priced at $1.00 each. Last week, the store offered a promotion under which customers purchasing one candy bar at full price could purchase a second candy bar for $0.50. A third candy bar would cost $1.00, a fourth would cost $0.50, and so on.

If, in a single transaction during the promotion, Rajiv spent D dollars on N candy bars, where D and N are integers, is N odd?

(1) D is prime.

(2) D is not divisible by 3.

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Re: At a particular store, candy bars are normally priced at $1. [#permalink]

15 Jan 2013, 06:37

trex16864 wrote:

1 candy cost 1
2 candies cost 1+.50=1.50 ( here D is not an integer, hence we cannot buy 2 candies . so we can reject all cases where D is non Integer)
3 candies cost 1.50 +1 =2.50
4 candies cost 2.50+.50= 3
5 candies cost 3+1= 4
6 candies cost 4+.50= 4.50
7 candies cost 4.50+1=5.50
8 candies cost 5.50.+.50= 6
9 candies cost 6+1= 7
.....
13 candies cost =10

(i) D is prime
D=3 and N=4 (N is even)
D=7 N=9 (N is odd )

not sufficient

(ii) D is not Divisible by 3

D=1 N=1
D=4 N =5
D=7 N=9
D=10 N=13

so we see if D is not divisible 3 then N is always odd.

Hence B is sufficient

Hope it's clear
_________________

Trying to contribute in my small way.

Re: At a particular store, candy bars are normally priced at $1. [#permalink] 15 Jan 2013, 06:37

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At a particular store, candy bars are normally priced at $1.

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At a particular store, candy bars are normally priced at $1.

At a particular store, candy bars are normally priced at $1.

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