At a picnic there were 3 times as many adults as children : GMAT Problem Solving (PS)
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At a picnic there were 3 times as many adults as children

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At a picnic there were 3 times as many adults as children [#permalink]

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26 Nov 2012, 21:56
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At a picnic there were 3 times as many adults as children and twice as many women as men. If there was a total of x men, women, and children at the picnic, how many men were there, in terms of x?

A. x/2
B. x/3
C. x/4
D. x/5
E. x/6
[Reveal] Spoiler: OA

Last edited by Bunuel on 24 Apr 2016, 21:31, edited 2 times in total.
Renamed the topic.
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Re: At a picnic there were 3 times as many adults as children [#permalink]

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26 Nov 2012, 23:53
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saxenarahul021 wrote:
At a picnic there were 3 times as many adults as children and twice as many women as men. If there was a total of x men, women, and children at the picnic, how many men were there, in terms of x?

A. x/2
B. x/3
C. x/4
D. x/5
E. x/6

Hii.
I am assuming that the question is "what fraction of men were there?".
Pick a smart number such as:
$$Adults-->18$$
Since the children are three times as many as children, hence $$Children-->6$$
Further, the adults comprise of Men and women.
The given ratio of $$\frac{#women}{#men} = \frac{2}{1}$$,
therefore $$#women=12, # men=6$$.
Since the total is Adults+children, i.e. 24.
Therefore fraction of men will be $$\frac{6}{24} or \frac{x}{4}$$
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Re: At a picnic there were 3 times as many adults as children [#permalink]

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27 Nov 2012, 01:38
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saxenarahul021 wrote:
At a picnic there were 3 times as many adults as children and twice as many women as men. If there was a total of x men, women, and children at the picnic, how many men were there, in terms of x?

A. x/2
B. x/3
C. x/4
D. x/5
E. x/6

Say there are 2 women and 1 man (twice as many women as men).

Thus there are 2+1=3 adults and 1 child (3 times as many adults as children) --> x=3+1=4 (total # of people).

Hence, the number of men in terms of x is x/4.

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Re: At a picnic there were 3 times as many adults as children [#permalink]

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29 May 2014, 05:56
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A=M+W=3C
W=2M

Then M=C

M+W+C=X

Then 2M+W=X
4M=X

M=X/4

Hope this clarifies
Cheers!
J
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Re: At a picnic there were 3 times as many adults as children [#permalink]

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03 Apr 2016, 05:45
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Re: At a picnic there were 3 times as many adults as children [#permalink]

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24 Apr 2016, 19:15
Bunuel, I understand your solution, but still am a little confused. The problem says three times as many adults as kids and two times as many women as men, so I had the following:

Kids: 6

Women: 16 (2/3 * 24 above)
Men: 8 (1/3 * 24 above)

so: Men / (Men + Women + Kids) --> 8/30

How should I know Men and Women don't include the kids, because they 'boys vs. girls'?

Thanks! I appreciate all you do the forum, you're super helpful.

Michael
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Re: At a picnic there were 3 times as many adults as children [#permalink]

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25 Apr 2016, 06:38
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mdacosta wrote:
Bunuel, I understand your solution, but still am a little confused. The problem says three times as many adults as kids and two times as many women as men, so I had the following:

Kids: 6

Women: 16 (2/3 * 24 above)
Men: 8 (1/3 * 24 above)

so: Men / (Men + Women + Kids) --> 8/30

How should I know Men and Women don't include the kids, because they 'boys vs. girls'?

Thanks! I appreciate all you do the forum, you're super helpful.

Michael

Women/men refers to adults. If it were otherwise it would be female/male instead.
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Re: At a picnic there were 3 times as many adults as children   [#permalink] 25 Apr 2016, 06:38
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