At a picnic there were 3 times as many adults as children

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At a picnic there were 3 times as many adults as children [#permalink]

26 Nov 2012, 22:56

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At a picnic there were 3 times as many adults as children and twice as many women as men. If there was a total of x men, women, and children at the picnic, how many men were there, in terms of x?

A. x/2
B. x/3
C. x/4
D. x/5
E. x/6

Last edited by Bunuel on 27 Nov 2012, 02:27, edited 1 time in total.

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Re: At a picnic there were 3 times [#permalink]

27 Nov 2012, 00:53

saxenarahul021 wrote:

Hii.
I am assuming that the question is "what fraction of men were there?".
Answer must be C.
Pick a smart number such as:
Adults-->18
Since the children are three times as many as children, hence Children-->6
Further, the adults comprise of Men and women.
The given ratio of \frac{#women}{#men} = \frac{2}{1},
therefore #women=12, # men=6.
Since the total is Adults+children, i.e. 24.
Therefore fraction of men will be \frac{6}{24} or \frac{x}{4}
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Re: At a picnic there were 3 times as many adults as children [#permalink]

27 Nov 2012, 02:38

saxenarahul021 wrote:

Say there are 2 women and 1 man (twice as many women as men).

Thus there are 2+1=3 adults and 1 child (3 times as many adults as children) --> x=3+1=4 (total # of people).

Hence, the number of men in terms of x is x/4.

Answer: C.
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Re: At a picnic there were 3 times as many adults as children [#permalink] 27 Nov 2012, 02:38

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At a picnic there were 3 times as many adults as children

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At a picnic there were 3 times as many adults as children

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