saxenarahul021 wrote:

At a picnic there were 3 times as many adults as children and twice as many women as men. If there was a total of x men, women, and children at the picnic, how many men were there, in terms of x?

A. x/2

B. x/3

C. x/4

D. x/5

E. x/6

Hii.

I am assuming that the question is "what fraction of men were there?".

Answer must be C.

Pick a smart number such as:

\(Adults-->18\)

Since the children are three times as many as children, hence \(Children-->6\)

Further, the adults comprise of Men and women.

The given ratio of \(\frac{#women}{#men} = \frac{2}{1}\),

therefore \(#women=12, # men=6\).

Since the total is Adults+children, i.e. 24.

Therefore fraction of men will be \(\frac{6}{24} or \frac{x}{4}\)

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