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# At least 100 students at a certain high school study

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Intern
Joined: 01 Aug 2007
Posts: 31
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Kudos [?]: 1 [1] , given: 0

At least 100 students at a certain high school study [#permalink]  31 Aug 2007, 09:25
1
KUDOS
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Difficulty:

5% (low)

Question Stats:

100% (02:11) correct 0% (00:00) wrong based on 2 sessions
At least 100 students at a certain high school study Japanese. If 4 percent of the students at the school who study French also study Japanese, do more students at the school study French than Japanese?

1) 16 students at the school study both French and Japanese
2) 10 percent of the students at the school who study Japanese also study French
VP
Joined: 10 Jun 2007
Posts: 1469
Followers: 5

Kudos [?]: 84 [2] , given: 0

Re: Venn - DS - GMATPrep [#permalink]  31 Aug 2007, 12:46
2
KUDOS
jp888 wrote:
At least 100 students at a certain high school study Japanese. If 4 percent of the students at the school who study French also study Japanese, do more students at the school study French than Japanese?

1) 16 students at the school study both French and Japanese
2) 10 percent of the students at the school who study Japanese also study French

B.

You are trying to find if F/J > 1?
(1) 16 students study both Japanese and French, that's 4% of the total number of students given from the question. So you have
16 = (4/100) * Total
Total = 400 students
You know that at least 100 students study Japanese and 16 studied both. So it could be that 101 students studied Japanese 299 studied French, or vice versa. INSUFFICIENT

(2) (10/100)*J = (4/100)*Total = (4/100)*(J+F)
=> F/J > 3/2
SUFFICIENT
Director
Joined: 22 Aug 2007
Posts: 573
Followers: 1

Kudos [?]: 7 [1] , given: 0

Re: Venn - DS - GMATPrep [#permalink]  31 Aug 2007, 17:02
1
KUDOS
jp888 wrote:
At least 100 students at a certain high school study Japanese. If 4 percent of the students at the school who study French also study Japanese, do more students at the school study French than Japanese?

1) 16 students at the school study both French and Japanese
2) 10 percent of the students at the school who study Japanese also study French

I got B

used a little different approach for 2nd statement

You are trying to find if F/J > 1?

1 st- copied from bbk post

(1) 16 students study both Japanese and French, that's 4% of the total number of students given from the question. So you have
16 = (4/100) * Total
Total = 400 students
You know that at least 100 students study Japanese and 16 studied both. So it could be that 101 students studied Japanese 299 studied French, or vice versa. INSUFFICIENT

(2) since # of students studying both is the same, I mean it is one.
we have 0.04(French)=0.1(Japanese)----->ratio of French to Japanese is more than 1

Sufficient
Director
Joined: 22 Aug 2007
Posts: 573
Followers: 1

Kudos [?]: 7 [0], given: 0

Re: Venn - DS - GMATPrep [#permalink]  31 Aug 2007, 17:07
bkk145 wrote:
jp888 wrote:
At least 100 students at a certain high school study Japanese. If 4 percent of the students at the school who study French also study Japanese, do more students at the school study French than Japanese?

1) 16 students at the school study both French and Japanese
2) 10 percent of the students at the school who study Japanese also study French

B.

You are trying to find if F/J > 1?
(1) 16 students study both Japanese and French, that's 4% of the total number of students given from the question. So you have
16 = (4/100) * Total
Total = 400 students
You know that at least 100 students study Japanese and 16 studied both. So it could be that 101 students studied Japanese 299 studied French, or vice versa. INSUFFICIENT

(2) (10/100)*J = (4/100)*Total = (4/100)*(J+F)
=> F/J > 3/2
SUFFICIENT

Is not

total=F+J-both(F&J)...?

though ultimate result does not change.
Re: Venn - DS - GMATPrep   [#permalink] 31 Aug 2007, 17:07
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