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At RW Press, the advertising rate, a, is inversely [#permalink]
24 Oct 2012, 03:46

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Question Stats:

41% (03:06) correct
59% (02:00) wrong based on 61 sessions

At RW Press, the advertising rate, a, is inversely proportional to the productivity measure, b, which, in turn, is inversely proportional to the labor cost, c. Is the labor cost at least 200 when the productivity measure is at least 100?

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
31 Oct 2012, 05:22

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This post received KUDOS

LM wrote:

At RW Press, the advertising rate, a, is inversely proportional to the productivity measure, b, which, in turn, is inversely proportional to the labor cost, c. Is the labor cost at least 200 when the productivity measure is at least 100?

(1) When C\geq{100}, B\geq{50}

(2) When C=100, a=100

Hi,

Based on Q's we can say that

a=k1/b where K1 is a constant and a -A.R and b is Productivity ----> Eq 1 b=K2/C where K2 is constant C is labour cost----> Eq 2

As per St 1 When C>/100, B>/50 ---> When C =100, B=50, Value of K2 is 5000 Putting B value as 100 in Eq 2, we can find value of C

St 2

Solving in similar way, we end up only with ratio of K1/K2 and hence cannot find value of C against given value of B

My ans choice is A _________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

At RW Press, the advertising rate, a, is inversely [#permalink]
07 May 2013, 23:24

At RW Press, the advertising rate, a, is inversely proportional to the productivity measure, b, which, in turn, is inversely proportional to the labor cost, c. Is the labor cost at least 200 when the productivity measure is at least 100?

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
08 May 2013, 00:13

Until the OA is posted, this answer will be based on my own understanding, therefore susceptible to be incorrect.

The wording of this problem seems off to me. Anyway, let's solve this.

First of all, we need to understand and rephrase the problem.

We are told that the advetising rate "a" is inversely proportional to the productivity measure "b". Algebraically it means that there's a constant C such as : a=\frac{C}{b} (1) Likewise, we are told that the productivity measure "b" is inversely proportional to the labor cost "c". Algebraically it means that there's a constant D such as : b = \frac{D}{c} (2)

So we're told that to see whether the labor cost is at least 200 when the productivity measure is at least 100. Meaning that we need to find the value of the constant D.

Statement 1 : whenc >=100 then b >=50

Using equation (2), we get : D = b*c which means that given the statement, D >= 5000. If we consider the lowest possible value of D, i.e 5000, we get for b >= 100, \frac{D}{c} >= 100, meaning that \frac{5000}{c} >=100, therefore c <= 50.

Which means that the labor cost will be at most 50 when the productivity measure is at least 100 given D = 5000. In fact the more D increases, the more c decreases. So statement 1 is sufficient.

Statement 2 : when c = 100 then a = 100

Since a and c are not directly linked, then using both equations 1 & 2, we can find the link between the two variables :

We have : a=\frac{C}{b} and b = \frac{D}{c} Therefore, by putting b's expression in a, we get a = c*\frac{C}{D}

Since a = c, then we get C = D. And since there's no further information to be gained from this statement (remember that we're looking for D's value), then this statement is insufficient.

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
08 May 2013, 04:57

Expert's post

mannava189 wrote:

At RW Press, the advertising rate, a, is inversely proportional to the productivity measure, b, which, in turn, is inversely proportional to the labor cost, c. Is the labor cost at least 200 when the productivity measure is at least 100?

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
06 Feb 2014, 01:32

My approach was very simple.

If two variables are inversely proportional, it simply means if one goes up then other goes down and vice versa.

Stmt 1 then gives straight forward NO answer to our question. when C>=100 B>=50. If B increases to 100 then C decreases further and will be <100. Hence C cannot be >=200 when B>=100. Sufficient.

Stmt 2 Is a bit tricky. Nothing is mentioned about B and we just know the relation between a & b. b & c.

given a=100 and c=100.

Now if a goes up b comes down. thus c increases.

if b were 900, increasing a & c to >=200 may have b at 400 or 100. we don't know. hence insufficient.

A is the answer. _________________

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Re: At RW Press, the advertising rate, a, is inversely
[#permalink]
06 Feb 2014, 01:32