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# At Springfield High, three-fourths of the male students and

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Senior Manager
Status: D-Day is on February 10th. and I am not stressed
Affiliations: American Management association, American Association of financial accountants
Joined: 12 Apr 2011
Posts: 275
Location: Kuwait
Schools: Columbia university
Followers: 4

Kudos [?]: 21 [0], given: 52

At Springfield High, three-fourths of the male students and [#permalink]  16 Jan 2012, 09:50
00:00

Difficulty:

5% (low)

Question Stats:

100% (02:49) correct 0% (00:00) wrong based on 6 sessions
At Springfield High, three-fourths of the male students and one-half of the female students speak a foreign language. If the number of males is two-thirds the number of females, what fraction of the students speak a foreign language?

a)1/3

b)2/3

c)1/2

d)4/3

e)3/5

I attempted this question but every time I get B. the OA is E

my approach was choosing a number, in this case I chose 120 as the total students, and solved it from there.

thanks
[Reveal] Spoiler: OA

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Senior Manager
Joined: 30 Aug 2009
Posts: 293
Location: India
Concentration: General Management
Followers: 2

Kudos [?]: 78 [1] , given: 5

Re: at Springfield High [#permalink]  16 Jan 2012, 11:27
1
KUDOS
manalq8 wrote:
At Springfield High, three-fourths of the male students and one-half of the female students speak a foreign language. If the number of males is two-thirds the number of females, what fraction of the students speak a foreign language?

a)1/3

b)2/3

c)1/2

d)4/3

e)3/5

I attempted this question but every time I get B. the OA is E

my approach was choosing a number, in this case I chose 120 as the total students, and solved it from there.

thanks

Consider total students = 120

given, M = (2/3)F

so F= 72 and M = 48

3/4M +1/2F speak foreign language = (3/4)* 48 + (1/2)*72 = 36+36 = 72

ratio = 72/120 = 3/5

E
Senior Manager
Status: D-Day is on February 10th. and I am not stressed
Affiliations: American Management association, American Association of financial accountants
Joined: 12 Apr 2011
Posts: 275
Location: Kuwait
Schools: Columbia university
Followers: 4

Kudos [?]: 21 [0], given: 52

Re: at Springfield High [#permalink]  16 Jan 2012, 13:42
oh I see. thanks alot. i was doing it 2/3 of 120.
thanks
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Sky is the limit

Manager
Status: MBA Aspirant
Joined: 12 Jun 2010
Posts: 180
Location: India
WE: Information Technology (Investment Banking)
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Kudos [?]: 17 [0], given: 1

Re: at Springfield High [#permalink]  16 Jan 2012, 19:34
Ans is E
let m be the no of male students
f be the no of female students and x be the total no of students
so m+f = x and given foreign language = 3/4m+1/2f
and m=2/3f on solving this we get the ans as E
Manager
Joined: 08 Sep 2011
Posts: 77
Concentration: Finance, Strategy
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Kudos [?]: 1 [0], given: 5

Re: At Springfield High, three-fourths of the male students and [#permalink]  23 Feb 2012, 09:52
may i ask why 120? why not 100

so the formula would be f+(2/3)f=100

f=60 a nice round number.
so m= 40

therefore 30 males and 30 females know a foreign language. that is 60/100 or 3/5

I personally find 100 an easier number and was wondering why you picked 120. But as long as it works it works
Re: At Springfield High, three-fourths of the male students and   [#permalink] 23 Feb 2012, 09:52
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