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At the Marseille port, a small cargo ship is loaded in 2.5

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At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink] New post 29 Aug 2013, 08:00
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At the Marseille port, a small cargo ship is loaded in 2.5 hours and a large cargo ship is loaded at double the rate in X hours. In terms of X, how many times does the load of a small cargo ship fit into a large cargo ship?

A. 2X/5
B. 5X/2
C. 5/4X
D. 4X/5
E. 5X/4

Last edited by Bunuel on 29 Aug 2013, 08:07, edited 1 time in total.
Renamed the topic and edited the question.
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink] New post 29 Aug 2013, 08:13
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Manaswita wrote:
At the Marseille port, a small cargo ship is loaded in 2.5 hours and a large cargo ship is loaded at double the rate in X hours. In terms of X, how many times does the load of a small cargo ship fit into a large cargo ship?

A. 2X/5
B. 5X/2
C. 5/4X
D. 4X/5
E. 5X/4


Say the large ship is twice as large as the small one (so say 2 loads of a small cargo ship fit into a large cargo ship). In this case at double the rate the 2 times larger ship will be loaded in the same 2.5 hours, so we'd have that x=2.5 hours. Now substitute x=2.5 into the answer choices to see which option gives 2. Only D fits.

Answer: D.
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink] New post 30 Aug 2013, 08:42
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D.

lets Say V1 is vol of small cargo and v2 is large cargo
r1 = v1/2.5
r2 = 2r1

x = v2/r2
x= v2/2v1/2.5

x= 5v2/4v1
v2/v1 = 4x/5 SO D
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink] New post 08 Sep 2013, 11:56
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Manaswita wrote:
At the Marseille port, a small cargo ship is loaded in 2.5 hours and a large cargo ship is loaded at double the rate in X hours. In terms of X, how many times does the load of a small cargo ship fit into a large cargo ship?

A. 2X/5
B. 5X/2
C. 5/4X
D. 4X/5
E. 5X/4



Sol:

work done by small ship = A (rate ) * 5/2 (time)= 5A/2

Work done by large ship = B(rate)* T = 2A*X

ratio = Large/small ship = 2AX/(5A/2) = 4X/5
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink] New post 24 Sep 2013, 22:35
Rate Time Work

1/2.5 2.5 1
2/2.5 X (2/2.5)X

1* What = 2/2.5 X

What = (2/2.5)X

Hence (D)
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink] New post 16 Apr 2014, 01:38
Work = rate *time;

r1 t1 = 2.5 * ra;
r2t2 = X*2 rb;

2.5 * ra = X * rb;

ratio = 4X/5;
Re: At the Marseille port, a small cargo ship is loaded in 2.5   [#permalink] 16 Apr 2014, 01:38
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