At the Marseille port, a small cargo ship is loaded in 2.5 : GMAT Problem Solving (PS)
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# At the Marseille port, a small cargo ship is loaded in 2.5

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At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink]

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29 Aug 2013, 08:00
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Question Stats:

78% (02:34) correct 22% (01:28) wrong based on 67 sessions

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At the Marseille port, a small cargo ship is loaded in 2.5 hours and a large cargo ship is loaded at double the rate in X hours. In terms of X, how many times does the load of a small cargo ship fit into a large cargo ship?

A. 2X/5
B. 5X/2
C. 5/4X
D. 4X/5
E. 5X/4
[Reveal] Spoiler: OA

Last edited by Bunuel on 09 Oct 2016, 23:50, edited 2 times in total.
Renamed the topic and edited the question.
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink]

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29 Aug 2013, 08:13
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Manaswita wrote:
At the Marseille port, a small cargo ship is loaded in 2.5 hours and a large cargo ship is loaded at double the rate in X hours. In terms of X, how many times does the load of a small cargo ship fit into a large cargo ship?

A. 2X/5
B. 5X/2
C. 5/4X
D. 4X/5
E. 5X/4

Say the large ship is twice as large as the small one (so say 2 loads of a small cargo ship fit into a large cargo ship). In this case at double the rate the 2 times larger ship will be loaded in the same 2.5 hours, so we'd have that x=2.5 hours. Now substitute x=2.5 into the answer choices to see which option gives 2. Only D fits.

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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink]

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30 Aug 2013, 08:42
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D.

lets Say V1 is vol of small cargo and v2 is large cargo
r1 = v1/2.5
r2 = 2r1

x = v2/r2
x= v2/2v1/2.5

x= 5v2/4v1
v2/v1 = 4x/5 SO D
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink]

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08 Sep 2013, 11:56
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Manaswita wrote:
At the Marseille port, a small cargo ship is loaded in 2.5 hours and a large cargo ship is loaded at double the rate in X hours. In terms of X, how many times does the load of a small cargo ship fit into a large cargo ship?

A. 2X/5
B. 5X/2
C. 5/4X
D. 4X/5
E. 5X/4

Sol:

work done by small ship = A (rate ) * 5/2 (time)= 5A/2

Work done by large ship = B(rate)* T = 2A*X

ratio = Large/small ship = 2AX/(5A/2) = 4X/5
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink]

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24 Sep 2013, 22:35
Rate Time Work

1/2.5 2.5 1
2/2.5 X (2/2.5)X

1* What = 2/2.5 X

What = (2/2.5)X

Hence (D)
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink]

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16 Apr 2014, 01:38
Work = rate *time;

r1 t1 = 2.5 * ra;
r2t2 = X*2 rb;

2.5 * ra = X * rb;

ratio = 4X/5;
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink]

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27 Nov 2014, 08:34
Let Small ship capacity be 'S'
Large ship capacity be 'L'

Form question -- small cargo ship is loaded in 2.5 hours, the rate at which the small ship loaded is S/2.5
-- large cargo ship is loaded at double the rate in X hours, the rate at which the large ship is loaded is L/x

Also, from question -- a large cargo ship is loaded at double the rate , so L/x = S/2.5 *2
L = S * X* 2/5 *2
L= S *(4X/5)
Hence 'D'
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink]

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27 Nov 2014, 22:45
Time ............... Rate .............. Work

2.5 ..................... $$\frac{1}{2.5}$$ ................. 1 (Small ship)

x .......................... $$\frac{2}{2.5}$$ ..................... $$\frac{2x}{2.5} = \frac{4x}{5}$$ (Big Ship; twice the rate of small ship)

Load in big ship is $$\frac{4x}{5}$$ times that of small ship

Bunuel: Kindly update OA for this question. Thanks
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Re: At the Marseille port, a small cargo ship is loaded in 2.5 [#permalink]

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08 May 2016, 04:08
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Re: At the Marseille port, a small cargo ship is loaded in 2.5   [#permalink] 08 May 2016, 04:08
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