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# At the same time, Jim and Tony biked from home to their

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At the same time, Jim and Tony biked from home to their [#permalink]

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12 Jan 2006, 04:53
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At the same time, Jim and Tony biked from home to their school. If their respective speed in the whole trip are constant, how much time earlier will Jim arrive than Tony?

1) The distance between home and school is 200 miles
2) Jim bikes 10 miles per hour faster than Tony
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12 Jan 2006, 05:04
E) We do not know the ratio between their respective speeds
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12 Jan 2006, 06:38
its between C or E, but I am going with E, because as BG mentioned, we dont know what those relative speeds were, and without that info we cannot calculate a definite time.
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12 Jan 2006, 08:49
E. Need some way to figure out Tony's speed, right?
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12 Jan 2006, 10:35
E. We need speed of one of the cyclists. Their relative constant speeds aren't enought to solve for time.
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12 Jan 2006, 23:21
E... both r INSUFF...we need to know the speeds.
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13 Jan 2006, 03:59
oa is E

n=speed of tony
m=speed of mary

s=d/t

abs(d/m-d/n) = d(n-m)/mn

I. dont know what m, n are

II. dont know what m,n or d are

both. dont know what m, n are.
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13 Jan 2006, 04:24
joemama142000 wrote:
At the same time, Jim and Tony biked from home to their school. If their respective speed in the whole trip are constant, how much time earlier will Jim arrive than Tony?

1) The distance between home and school is 200 miles
2) Jim bikes 10 miles per hour faster than Tony

E simple reasoning
1)insuf cause we don't know distance between (which )home and school is 200 miles
2) Jim bikes 10 miles per hour faster than Tony[/quote]Insuff cause we don't know whats Tony's speed
Hence E
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13 Jan 2006, 13:38
e becuse we dont know either person's rate (necessary for solving the eqquation) or at least a ratio between their rates so we can respond with a ratio (ie m=1/2t)

kind of an easy one, no?
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13 Jan 2006, 13:39
Yurik79, it can be inferred from the question stem that both homes are 200m from the school (I hope!!)
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