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Re: At the same time, Jim and Tony biked from home to their [#permalink]
E. Need some way to figure out Tony's speed, right?
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Re: At the same time, Jim and Tony biked from home to their [#permalink]
E. We need speed of one of the cyclists. Their relative constant speeds aren't enought to solve for time.
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Re: At the same time, Jim and Tony biked from home to their [#permalink]
E... both r INSUFF...we need to know the speeds.
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Re: At the same time, Jim and Tony biked from home to their [#permalink]
oa is E

n=speed of tony
m=speed of mary

s=d/t

abs(d/m-d/n) = d(n-m)/mn

I. dont know what m, n are

II. dont know what m,n or d are

both. dont know what m, n are.
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Re: At the same time, Jim and Tony biked from home to their [#permalink]
joemama142000 wrote:
At the same time, Jim and Tony biked from home to their school. If their respective speed in the whole trip are constant, how much time earlier will Jim arrive than Tony?

1) The distance between home and school is 200 miles
2) Jim bikes 10 miles per hour faster than Tony

E simple reasoning
1)insuf cause we don't know distance between (which )home and school is 200 miles
2) Jim bikes 10 miles per hour faster than Tony[/quote]Insuff cause we don't know whats Tony's speed
Hence E
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Re: At the same time, Jim and Tony biked from home to their [#permalink]
e becuse we dont know either person's rate (necessary for solving the eqquation) or at least a ratio between their rates so we can respond with a ratio (ie m=1/2t)

kind of an easy one, no?
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Re: At the same time, Jim and Tony biked from home to their [#permalink]
Yurik79, it can be inferred from the question stem that both homes are 200m from the school (I hope!!)



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